Answer: x=6
Step-by-step explanation:
Let's solve your equation step-by-step.
4+3(2x−4)=28
Step 1: Simplify both sides of the equation.
4+3(2x−4)=28
4+(3)(2x)+(3)(−4)=28(Distribute)
4+6x+−12=28
(6x)+(4+−12)=28(Combine Like Terms)
6x+−8=28
6x−8=28
Step 2: Add 8 to both sides.
6x−8+8=28+8
6x=36
Step 3: Divide both sides by 6.
6x
6
=
36
6
Answer:
D. About 800 years
Step-by-step explanation:
Use the half-life equation:
A = A₀ (½)ⁿ
where A is the final amount,
A₀ is the initial amount,
and n is the number of half-lives.
0.90A₀ = A₀ (½)ⁿ
0.90 = (½)ⁿ
To solve for n, take log of both sides:
log 0.9 = n log 0.5
n = (log 0.9) / (log 0.5)
n = 0.152
It takes 0.152 half-lives. The half-life of carbon-14 is 5730 years.
0.152 × 5730 years = 871 years
The closest answer is D.
Answer:
Photomath help you get the answer
Step-by-step explanation:
Answer: x = 1, y = -2
Step-by-step explanation:
-9x+2y=-13
x= 13/9 + 2/9y
2x-9y=20
2(13/9+2/9y)-9y=20
<em>Substitute y with -2.</em>
<em />
x= 13/9+2/9(-2)
<em>After solving you'll see that 1 is a possible solution for x.</em>
<em />
Check your answer
-9x+2y=-13
-9x1+2(-2) = -13
2x-9y=20
2x1-9(-2) = 20
-13 = -13
20 = 20
Therefore, x=1 and y=-2
Answer:
Step-by-step explanation:
Given
Required
Determine the number of miles driven on the highway and on the city
Represent the gallons used on highway with h and on city with c.
So, we have:
---- gallons used
and
--- distance travelled
In the first equation, make c the subject
Substitute 10 - h for c in the second equation
Open bracket
Collect like terms
Make h the subject
Substitute 5 for h in
If on the highway, he travels 31 miles per gallon, then his distance on the highway is:
If in the highway, he travels 26 miles per gallon, then his distance on the highway is:
