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2 years ago

Write an expression with parentheses (don’t simplify!) to represent the following quantity:

Mathematics

2 answers:

lyudmila [28]2 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

Express as per statement

$\frac{170}{(25+9)}$

spin [16.1K]2 years ago

5 0

Answer:

See below.

Step-by-step explanation:

The sum of 25 + 9 is written in parentheses ;- (25 + 9).

This is divided into 170 so the expression is 170 / (25 + 9).

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use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

5 0

3 years ago

What are the discontinuity and zero of the function f(x) = quantity x squared plus 6 x plus 8 end quantity over quantity x plus

Tcecarenko [31]

Answer:

Discontinuity at (-4,-2), zero at (-2,0).

Step-by-step explanation:

We are given that a function

$f(x)=\frac{x^2+6x+8}{x+4}$

We have to find the discontinuity and zero of the given function.

Discontinuity: It is that point where the function is not defined.

It makes the function infinite.

$f(x)=\frac{x^2+4x+2x+8}{x+4}$

$f(x)=\frac{(x+4)(x+2)}{x+4}$

When x=-4 then

$f(-4)=\frac{0}{0}$ It is indeterminate form

Function is not defined

After cancel out x+4 in numerator and denominator then we get

$f(x)=x+2$

Substitute x=-4

$f(-4)=-4+2=-2$

Therefore, the point of discontinuity is (-4,-2).

Zero: The zero of the function is that number when substitute it in the given function then the function becomes zero.

When substitute x=-2

Then , $f(0)=-2+2=0$

The function is zero at (-2,0).

Hence, option C is true.

6 0

2 years ago

What is the next term in the sequence if the first four are as follows.

max2010maxim [7]

4x3=12x3=36x3=108x3=324 there is you answer and how i got it hope this helps

8 0

3 years ago

What is the measurements the for the angles

koban [17]

The angle TQS is 74° and the angle SQR is 106°

5 0

2 years ago

frank has two same size rectangles divided into the same number of equal parts. one rectangle has 3/4 of the parts shaded, and t

lidiya [134]

This question basically asks for the LCM of 3 and 5, which is 3 x 5 =15
This is the answer: 15
Check : The first rectangle had 1/3 shaded; ( one in every three parts)
So for 15 parts altogether, 5 would be shaded ( 1/3 = 5/15)
The second rectangle had 2/5 shaded ( two for every five parts)
So for 15 parts altogether, 6 would be shaded (2/5 = 6/15)

6 0

2 years ago