Answer:
p²q³ + pq and pq(pq² + 1)
Step-by-step explanation:
Given
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Required
Collect like terms
We start by rewriting the expression
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Collect like terms
3p²q² -3p²q² - 3p²q³ +4p²q³ + pq
Group like terms
(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq
Perform arithmetic operations on like terms
(0) - (-p²q³) + pq
- (-p²q³) + pq
Open bracket
p²q³ + pq
The answer can be further simplified
Factorize p²q³ + pq
pq(pq² + 1)
Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)
Answer and explanation:
(x + 6)(x + 7)
List the multiples of 42
42: 1 2 3 6 7 14 21 42
Then see which of the multiples add up to 13
1 x 42 = 42 --> 1 + 42 
13
2 x 21 = 42 --> 2 + 21 13
3 x 14 = 42 --> 3 + 14 13
6 x 7 = 42 --> 6 + 7 = 13
Answer:
since the unknown amount can buy 100 pencils
he bought 70 pencils
therefore $4.50 can buy 30 pencils
so 1 pencils cost $4.50 /30=0.15
B is greater than 1, so B>1
That is correct since the line in T is not straight it would eventually hit the third quadrant
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