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3 years ago

3. Find the midpoint between the following points. (-2,-5) and (-3,1)

Mathematics

1 answer:

Vadim26 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

(x₁, y₁) = (-2 , -5) & (x₂ , y₂) = (-3 , 1)

Midpoint = $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

$=(\frac{-2 + [-3]}{2} ,\frac{-5 + 1}{2})\\\\\\=(\frac{-5}{2} , \frac{-4}{2})\\\\=(-2.5, -2)$

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Answer:

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Determine to the nearest and tenth the surface area of a tin can with a radius of 8 centimeters and a height of 16 centimeters

trapecia [35]

Answer:

1206 square centimeters

Step-by-step explanation:

Hello, I can help you with that

a tin is a cylinder,a cylinder is formed by 2 circles anda 1 rectangle

let's remember

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Area of the rectangle

$A_{r}=length *wide\\$

the length of the rectangle is the height of the tin (16 cm)

and the wide is equal to the perimeter of the circle

perimeter of the circle(P)

$P=2*\pi *radius$

so, the area of the rectangle is

$A_{r}=length *wide\\\\A_{r}=heigth *2*\pi *radius$

Step one

find the total area:

the total area is equal to 2 circles + 1 rectangle

$A_{total}=(2* \pi *radius^{2} )+(height*2*\pi *radius)$

Step two

put the values into the equation

height = 16 cm

radius= 8 cm

$A_{total}=(2* \pi *radius^{2} )+(height*2*\pi *radius)\\A_{total}=(2* \pi )+(16*2*\pi *8)\\A_{total}=(128* \pi )+(256*\pi )\\A_{total}= 378 \pi\\ A_{total}=1206.37$

so, the total area is 1206.37 square centimeters

I hope it helps, have a great day.

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2 years ago

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3 years ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

aleksandrvk [35]

Answer:

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3 years ago

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3. Find the midpoint between the following points. (-2,-5) and (-3,1) ​

3. Find the midpoint between the following points. (-2,-5) and (-3,1)