Sample space for:
First shooting a basketball. Two options: X or O
Then rolling a die. Six options: 1, 2, 3, 4, 5, or 6
Sample space:
X1
X2
X3
X4
X5
X6
O1
O2
O3
O4
O5
O6
Answer: Options:
A. X1
C. O6
F. X6
Answer: x = 30' , y = 45'
hope this helps
Step-by-step explanation:
U is 90' it's a right triangle
well simple VRT you already know 2 angles which is 60' and 90'
R = 60'
V = 90'
T = x
you know that a triangle = 180'
so you do
180 - 60 - 90 = x
30 = x
if you want to do y
then you already know that U is 90' on both sides.
since you also know S,
S = 45'
U = 90'
V = y
180 - 90 - 45 = y
45 = y
Step one know that across from 128 is 128 because of vertical angles
step two a straight line =180 so 128 -180 = 52
step three know you know 3k+4=52 so subtract 4 from 52 and that gives you 48 then divide by 3 to find k and 48/3 is 16
so k +16
because 16x3 is 48 then add 4 which is 52 and 52 plus 128 is 180
Answer:
1. 
2. ![x=\pm7i[tex]3.[tex]\pm 12x =a](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fp%3E%3Cp%3E3.%5Btex%5D%5Cpm%2012x%20%3Da)
4. 22
Step-by-step explanation:
1. 
2. 
![x=\pm7i[tex]3. Area of square = [tex]a^{2}](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E3.%20Area%20of%20square%20%3D%20%5Btex%5Da%5E%7B2%7D)
Where a is the side
We are given an area o square = 
So, 
4. We are given that the solution of quadratic equation -9 and 9
So, equation becomes:
So, in the given equation 
z should be the number from which if we subtract 103 so we get 81
Substitute z = 22
Thus the value of z is 22
