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slavikrds [6]
3 years ago
9

90 juniors took different SAT-II tests. 40% more students took the Chemistry test than took the History test, and 50% more stude

nts took the Math test than took the Chemistry test. How many students took each test?
Mathematics
1 answer:
erastovalidia [21]3 years ago
4 0

Answer:


Step-by-step explanation:

4.5x=90

x=20 history

28 chemistry

42 math

They add to 90.  


History test=x

Chemistry test=1.4x

Math test=(1.5)(1.4)=2.1x

They add to 90

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At 1 p.m., the number of cars in a parking lot is 78. Given the formula found in the first part of the question, An=78⋅1.09n, es
Harrizon [31]

Answer:

At 6 p.m., the number of cars in a parking lot is 120

Step-by-step explanation:

At 1 p.m., the number of cars in a parking lot is 78.

Given,

A_n=78\cdot 1.09^n

Note that

A_0=78\cdot 1.09^0=78\cdot 1=78

So, 1 p.m. goes for n = 0, then

6 p.m. goes for n = 5

Thus,

A_5=78\cdot 1.09^5\approx 120

4 0
3 years ago
Help now fast..................................
Yuliya22 [10]

Answer:

C

Step-by-step explanation:

There are 6 units in the numberline, and 2 are shaded. So, 2/6 are shaded.

8 0
3 years ago
The functions r and s are defined as follows.
irina1246 [14]

Answer:

r(s(-2)) = -2

Step-by-step explanation:

We are given these following functions:

r(x) = -2x + 2

s(x) = x^2 - 2

Find the value of r(s (-2)).

First we find the composition of r and s functions. It is:

r(s(x)) = r(x^2-2) = -2(x^2-2) + 2 = -2x^2 + 6

At x = -2

r(s(-2)) = -2(-2)^2 + 6 = -8 + 6 = -2

r(s(-2)) = -2

8 0
3 years ago
Popcorn was donated for the school fair by 3 different popcorn vendors. They donated a total of 996 bags of popcorn. Each vendor
Marysya12 [62]

Answer:

let the of bag of vendors be X

3donate X bag to give 996

3×x=996

3x=996

divide both side by 3

3x\3=996\3

x=332

each vendor donated 332bags of popcorn

5 0
3 years ago
Read 2 more answers
Jerry planted a pine tree that was 5 feet tall and a maple tree that was 10 feet tall. The pine tree grew 3 feet taller per year
stich3 [128]

The initial length of the pine tree=5 feet.

Groth rate of pine tree =3 feet/year.

The initial length of the pine tree =10 feet.

Groth rate of the maple tree =2 feet/year.

After x years, the height of the pine tree= 5+3x feet and

after x years, the height of the maple tree= 10+2x feet.

The inequality for which, after x year, the pine tree is taller than the maple tree is

5+3x>10+2x

\Rightarrow x>5 .

The inequality for which, the pine tree is at least as tall as the maple tree is 5+3x\geq10+2x.

\Rightarrow x\geq 5 .

Again, after 3x years, the height of the pine tree= 5+3(3x)=5+9x feet and

after 2x years, the height of the maple tree= 10+2(2x)=10+4x feet.

The inequality for which, after 3x years, the pine tree is taller than the maple tree was after 2x years is

5+9x>10+4x

\Rightarrow 5x>5

\Rightarrow x>1.

The inequality for which, the pine tree is at least as tall as the maple tree is 5+9x\geq10+4x.

\Rightarrow 5x\geq5

\Rightarrow x\geq 1.

5 0
3 years ago
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