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4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr

Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) $P=P_0 (4)^{t/12}$ for I bacteria where t is no of minutes from start.

ii) $P=P_0 (4)^{t/10}$ for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = $3(4)^{5} =3072$

ii) II bacteria P = $3(4)^{4} =768$

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

$3(4)^{10}- 3(4)^{8} =2949120$

c) i) $P=P_0 (4)^{t/12}$ for I bacteria where t is no of minutes from start.

ii) $P=P_0 (4)^{t/10}$ for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

$i) P=3 (4)^{36/12}=192$

The rate may not be constant for a longer time. Hence this may not be accurate.

e) when splits into 2, we get

$P=P_o (2^t)$ where P0 is initial and t = interval of time

7 0

3 years ago

Simplify x + 6.2 + 8.5.<br><br> 6.2x + 8.5<br> x + 14.7<br> 14.7x

Sunny_sXe [5.5K]

Answer:

x + 14.7

Step-by-step explanation:

x + 6.2 + 8.5.

Combine like terms

x + 14.7

5 0

2 years ago

Read 2 more answers

On 1st January 2020, Laurie invests P dollars in an account that pays a nominal annual interest rate of 5.5%, compounded quarter

andrezito [222]

Answer:

1) The common ratio = 1.055

2) The year in which the amount of money in Laurie's account will become double is the year 2032

Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

Which is in the form of the sum of a geometric progression, Sₙ given as follows;

Sₙ = a + a × r + a × r² + a × r³ + ... + a × rⁿ

Where;

n = The number of years

Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

The common ratio = 1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

The number of years it will take for the amount of money in Laurie's account to double = n = 12.95 years

Therefore, the year in which the amount of money in Laurie's account will become double = 2020 + 12..95 = 2032.95 which is the year 2032

The year in which the amount of money in Laurie's account will become double = year 2032.

3 0

2 years ago

Evaluate the expression 5×5^2÷5-6

Anika [276]

Step-by-step explanation:

according to BODMAS

5×5^2÷5-6

5^2=25

5×25÷5-6

5×5-6

25-6=19

7 0

2 years ago

Select all of the following true statements if R = real numbers, I = integers, and W = {0, 1, 2, ...}.

Vinvika [58]

Answer and Step-by-step explanation:

We will begin to solve this problem by defining first what the sets' elements really are.

R consists of real numbers. This means that this set contains all the numbers, rational or not.

Z is composed of whole numbers. Integers include all negative and positive numbers as well as zero (it's basically a set of whole numbers and their negated values).

W, on the other hand, has 0,1,2, and its elements are onward. Those numbers are referred to as whole numbers.

W ⊂ Z is TRUE. Z contains all the numbers as stated earlier, and W is a subset of it.

R ⊂ W is FALSE. Not all numbers are complete numbers. Complete numbers must be rational and represented fractionless. These requirements are not met by those real numbers.

0 ∈ Z is TRUE. Zero is just an integer so it is a component of Z.

∅ ⊂ R is TRUE. A set i.e null be R subset, and each and every set is a general set. Moreover, there were not single elements in a null set, so it spontaneous became a non empty set subset through description as there is no element of R.

{0,1,2,...} ⊆ W is TRUE. The set on the left is precisely what is specified in the statement for problem for W. (The bar below the subset symbol simply implies that the subset is not rigid, because the set on the left may be equal to the set on the right. Without it, the argument would be incorrect, because a strict subset needs that the two sets not be identical).

-2 ∈ W is FALSE. W's only made up of whole numbers and not their negated equivalents.

4 0

3 years ago