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alexira [117]
4 years ago
7

What are the coordinates of the image of vertex D after a reflection across the x-axis?

Mathematics
1 answer:
Elena-2011 [213]4 years ago
4 0

Answer:

(-3,5) ia the answer

Step-by-step explanation:

It is because when you reflect it across the x axis the first coordinate will be negative and the second number is positive since its in the second square of the graph, so it is more of a resonable guess.

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In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.
artcher [175]

Answer:

21.9°

Step-by-step explanation:

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet. Find the measure of ∠H to the nearest tenth of a degree.

We solve this above question using the Sine rule

a/sin A = b/sin B

In ΔHIJ, the measure of ∠J=90°, HI = 8 feet, and JH = 1.9 feet.

Hence:

HI/∠J = JH/∠H

= 8/sin 90° = 1.9/sin ∠H

Cross Multiply

∠H = arc sin(sin 1.9 × 90/8)

∠H = 21.9°

5 0
3 years ago
What is the length of the base of a yield sign that has a height of 14 inches and has an area of 84 square inches? Write the num
Rufina [12.5K]
That's simple, it is 6. Hope this helps.
4 0
4 years ago
Read 2 more answers
Lance baked a pie Justin ate 2/3 of the pie and Joey ate 1/4 of the pie how much of the pie is left
zepelin [54]
1 - 2/3 - 1/4
= 1 - 8/12 - 3/12
= 1/12
8 0
3 years ago
Find h.<br> 11 in.<br> h = [?] in<br> in.<br> 14 in.<br> PLEASE OH PLEASE HELP ME IM DESPERATE
Sliva [168]

11^2 = h^2 + ( 14/2)^2

11^2 = h^2 + 7^2

121 = h^2 + 49

h^2 = 121 - 49

h^2 = 72

h = √72

4 0
3 years ago
Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
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