2 ways in solving this hope it helped
Im giving you instrutions to get the answer its simple:D
The figure above shows a circular sector OAB<span> , subtending an </span>angle<span> of θ radians ... The points A and B lie on the circle so that the </span>angle AOB<span> is 1.8 radians. .... c) </span>Calculate<span> the smallest </span>angle<span> of the </span>triangle<span>ABC , giving the answer in </span>degrees<span>, .... Given that the length of the arc AB is </span>48<span> cm , </span>find<span> the area of the shaded region</span><span>.
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the square root of 25 is 5
5x5=25
Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
Answer:
2:4
Step-by-step explanation: Subtract 1 from total amount then find the number of girls I think sorry
