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2 years ago

15

Alinethatincludesthepoint(2, 7)has slope of 5 . what isitsequationin slope -intercept form

1 answer:

Vesna [10]2 years ago

8 0

10? Im not sure though my friend just told me it was 10

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A line has a slope of -6 over 7. What is the slope of the line parallel to it? And what is the slope of the line perpendicular t

olga_2 [115]

The slope of the parallel line is -6/7
the slope of the perpendicular line is 7/6
the slope of the line = -6/7
the gradient of two parallel lines are equal
the product of the gradient of two perpendicular lines is -1
: the gradient m1*m2 = -1
m2= -1(-6/7)
m2= 7/6

3 0

3 years ago

Frick and frack are surveying the times it takes students to arrive at school from home. There are 2 main groups of commuters wh

noname [10]

Answer:

900

Step-by-step explanation:

divide 4

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3 years ago

Simplify 3^2 x 3^4 x 3^6 A3^10 B3^12 C3^48 D3^0

kvasek [131]

Answer:

$\boxed{\sf\: B)\:3^{12}}$

Step-by-step explanation:

$\sf 3^2\times \:3^4\times \:3^6$

<u>Apply exponent rule:</u>

$\hookrightarrow \boxed{\sf a^b\times \:a^c=a^{b+c}}$

$\sf 3^2\times \:3^4\times \:3^6$

$\sf 3^{2+4+6}$

Add the numbers:

$\sf 2+4+6=12$

$\sf \:3^{12}$

________________________________

7 0

2 years ago

Find the largest number which divides 149 and 101 , leaving remainder of 5

erik [133]

The answer to this problem is 48.

8 0

3 years ago

Which points lie on the line whose equation is 8x - 2y + 7 = -9? Select all that apply.

Anestetic [448]

Answer:

A.(-2, 0)

C. (-1.4)

Step-by-step explanation:

we know that

If a point lie on the line, then the point must satisfy the equation of the line (makes the equation true)

we have

$8x-2y+7=-9$

subtract 7 both sides

$8x-2y=-9-7$

$8x-2y=-16$

divide by 2 both sides

$4x-y=-8$

Substitute the value of x and the value of y of each point in the linear equation and analyze the result

<u><em>Verify each point</em></u>

case A) we have

(-2, 0)

For x=-2, y=0

substitute

$4(-2)-(0)=-8$

$-8=-8$ ---> is true

so

the point lie on the line

case B) we have

(1, 3)

For x=1, y=3

substitute

$4(1)-(3)=-8$

$1=-8$ ---> is not true

so

the point not lie on the line

case C) we have

(-1, 4)

For x=-1, y=4

substitute

$4(-1)-(4)=-8$

$-8=-8$ ---> is true

so

the point lie on the line

case D) we have

(1, -4)

For x=1, y=-4

substitute

$4(1)-(-4)=-8$

$8=-8$ ---> is not true

so

the point not lie on the line

case E) we have

(0, -1)

For x=0, y=-1

substitute

$4(0)-(-1)=-8$

$1=-8$ ---> is not true

so

the point not lie on the line

7 0

3 years ago