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3 years ago

Alinethatincludesthepoint(2, 7)has slope of 5 . what isitsequationin slope -intercept form

Mathematics

1 answer:

Vesna [10]3 years ago

8 0

10? Im not sure though my friend just told me it was 10

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(Do not use spaces. Use to represent exponents. Example 2^3 is 22.)

Alik [6]

Answer: y=6^x-3

It is a exponent form of graph, so first:

y=a^x-b

When b=0, the asymptote is y=0 but as the asymptote given is y=-3, b=-3

Second:

the y value increases 6, when x changes 0 to 1, so a=6

8 0

3 years ago

Read 2 more answers

1,236,840 in scientific notation.

Leni [432]

The answer is 123684 x 10^1. Hope i helped.(whatever comes after ^ is an exponent)

4 0

3 years ago

To be considered for pilot school, 12 students took a spatial reasoning test that resulted in this list of scores. Find the valu

lord [1]

Answer:

the 90th percentile is 145

Step-by-step explanation:

Data provided:

152 121 130 143 122 101 137 98 138 127 145 117

Number of students considered, n = 12

To find:

90th percentile

Now,

Step 1 : Arrange the data in ascending order

98, 101, 117, 121, 122, 127, 130, 137, 138, 143, 145, 152

Step 2 : Compute the position of the 90th percentile

position of the 90th percentile, i = (90% × n)

Thus,

i = 0.90 × 12

i = 10.8

Now,

Step 3 : Since, the index i is not an integer, round up to the nearest integer

i.e i = 11

Therefore,

The 90th percentile is the value in 11th position,

i.e 145

7 0

3 years ago

Why are chemical sense called behavioral barriers

iren [92.7K]

Answer:because it works different when you smell a chemical sense from then if you smell a regular sese.

Step-by-step explanation:

A regula sense like a fart might smell bad. But a chemical sense can burn your nostrils and burn you nose hairs causing you not to have good sent or to never smell again

3 0

3 years ago

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

5 0

3 years ago