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2 years ago

5

During the school week, joshua spent 3$ each day in lunch.On tuesday,he bought a 5$ ticket to the school and on friday he loaned

2$ to his friend.When he checked his wallet at the end of the day friday,he had 3$ left .how much money did he start the week with ?

1 answer:

suter [353]2 years ago

3 0

He started out with $25

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Let set C = {even numbers between 1 and 99} and set D = {numbers between 1 and 150 that are evenly divisible by 10}.

Alex

$C=\{2;\ 4;\ 6;\ 8;\ ...;\ 98\}\\\\D=\{10;\ 20;\ 30;\ 40;\ 50;\ 60;\ ...;\ 140\}\\\\C\ \cap\ D=\{10;\ 20;\ 30;\ 40;\ 60;\ 70;\ 80;\ 90\}\\\\Answer:\boxed{A}$

4 0

3 years ago

An NFL coach sometimes uses a defense that utilizes 3 defensive linemen, 4 linebackers, and 4 defensive backs. His roster (the p

Alexandra [31]

Answer:

68,600

Step-by-step explanation:

The order of the players is not important. For example, a defensive line of Shaq Lawson, Ed Oliver and Jerry Hughes is the same as a defensive line of Ed Oliver, Shaq Lawson and Jerry Hughes. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Defensive Lineman:

3 from a set of 8. So

$C_{8,3} = \frac{8!}{3!5!} = 56$

56 combinations of defensive lineman

Linebackers:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of linebackers

Defensive backs:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of defensive backs

How many different ways can the coach pick the 11 players to implement this particular defense?

56*35*35 = 68,600

68,600 different ways can the coach pick the 11 players to implement this particular defense

7 0

3 years ago

Find the equation of a line that passes through the point (-2,3) and has a gradient of 3.

nadya68 [22]

Answer:

y = 3x+9

Step-by-step explanation:

The standard form of equation of a line is in the form y = mx + c

m is the gradient

c is the y intercept

Get the y-intercept

Substitute m = 3 and the point (-2, 3) into the formula y = mx+c

3 = 3(-2) + c

3 = -6+c

c = 3+6

c = 9

Get the required equation;

y = 3x + 9

Hence the required equation is y = 3x+9

5 0

2 years ago

Klio2033 [76]

Answer:

10x-2y

Step-by-step explanation:

distribute for both of them then multiply both answers by 2 and add them

2(x+y)= (2x+2y) x2= 4x+4y

3(x-y)= (3x-3y) x2= 6x-6y

4x+4y+6x-6x

10x-2y

5 0

2 years ago

Help me pleaseeeeeeee

Hitman42 [59]

True i think I don’t really know

4 0

2 years ago