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vladimir1956 [14]
3 years ago
9

Substituition method 5x-3y+1=16 2x+5y=-6

Mathematics
1 answer:
laila [671]3 years ago
3 0
5x - 3y + 1 = 16 ⇒ 10x -    6y + 2 = 16
2x + 5y + 0 = -6 ⇒ <u>10x + 25y + 0 = -6</u>
                                         31y + 2 = 10
                                         <u>         -2    -2</u>
                                               <u>31y</u> = <u>8</u>
                                                31    31
                                                   y = 8/31
                            5x - 3(8/31) + 1 = 16
                              5x - 24/31 + 1 = 16
                                     5x + 7/31 = 16
                                    <u>        -7/31    -7/31</u>
                                                 <u>5x</u> = <u>10 24/31</u>
                                                  5           5
                                                   x = 2 24/155
                                             (x, y) = (2 24/155, 8/31)
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Answer:

Step-by-step explanation:

Recall that the ratio test is stated as follows:

Given a series of the form \sum_{n=1}^{\infty} a_n let L=\lim_{n\to \infty}\left|\frac{a_{n+1}}{a_n}\right|

If L<1, then the series converge absolutely, if L>1, then the series diverge. If L fails to exist or L=1, then the test is inconclusive.

Consider the given series \sum_{n=1}^{\infty} n! \cdot 112n. In this case, a_n =n! \cdot 112n, so , consider the limit

\lim_{n\to\infty} \frac{(n+1)! 112 (n+1)}{n! 112 n} = \lim_{n\to\infty}\frac{(n+1)^2}{n}

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7 0
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Determine the factors of x2 − 7x − 10. (5 points) a (x + 2)(x − 5) b Prime c (x − 2)(x + 5) d (x + 10)(x − 1)
Savatey [412]

For this case we must factor the following expression:

x ^ 2-7x-10

To factor, we must find two numbers that when added together give -7 and when multiplied by -10.

It is observed that there are not two whole numbers that comply with the aforementioned.

Thus, the following equation applies:

x = \frac {-b \pm\sqrt{b ^ 2-4 (a) (c)}} {2 (a)}

Where:

a = 1\\b = -7\\c = -10

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x = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (1) (- 10)}} {2 (1)}\\x = \frac {7 \pm \sqrt {49 + 40}} {2}\\x = \frac {7 \sqrt {89}} {2}

So, the roots are:

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x_ {1} =\frac {7+ \sqrt {89}} {2}\\x_ {2} =\frac {7- \sqrt {89}} {2}

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vichka [17]

Answer:

The answer to your question is the third option

Step-by-step explanation:

To know if two lines are parallel we must get their slopes if the slopes are equal, the lines are parallel.

Data

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B (3,6)

C(0,5)

D(1,9)

Formula

slope = \frac{y2 - y1}{x2 - x1}

Process

1.- Calculate the slope of line 1

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slope 1 = \frac{4}{1}

slope 1 = 4

2.- Calculate slope 2

slope 2 = \frac{9 - 5}{1 - 0}

slope 2 = \frac{4}{1}

slope 2 = 4

3.- Compare the slope

slope 1 = 4 and slope 2 = 4, both slope are equals, then the lines are parallel.

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