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Naily [24]
3 years ago
7

Which equation supports the given conjecture?

Mathematics
2 answers:
andre [41]3 years ago
7 0

The verified answer is wrong the correct answer is d 5 squared plus 6 squared. Because the question is asking for two consecutive integers and it wants an odd integer therefor d is the correct answer because it has to squared consecutive integers and an odd answer.

Hope i helped Mark as brainliest

Readme [11.4K]3 years ago
3 0
The first part says the sum of the squares of two consecutive integers or in other words (x)(x)+(x+1)(x+1) so we can cross out A because 2 and 3 are prime numbers (no factors)  we can cross out all the others because the square root of 52 is not an integer so any equation with 52 in it does not satisfy the requirement. so none of them are corect.  additionally, some of the equations are obviously false such as 52+62=61
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Answer:

Step-by-step explanation:

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Use the elimination method to solve the system of equations. 3x+2y=16 2x-2y=4​
Masteriza [31]

Answer:

x = 4; y = 2  

Step-by-step explanation:

(1)  3x + 2y = 16

(2)  2x – 2y =  4        Add (1) and (2)

              5x =  20     Divide each side by 5

(3)            x =    4      Substitute (3) into (2)

  2×4 – 2y =    4

       8 - 2y =     4     Subtract 16 from each side

            -2y =   -4     Divide each side by -2

              y =     2

<em>Check: </em>

(1)  3×4 + 2×2 = 16

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                  16 = 16

(2) 2×4 – 2×2 = 4

      8    -    4   = 4

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5 0
3 years ago
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The difference of twice a number G and 10 is 24.<br><br> Please help me as I'm stumped! Thank you!
arlik [135]
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There are 210210210 students in a twelfth grade high school class. 909090 of these students have at least one sister and 1051051
BlackZzzverrR [31]

Answer:

(1) The value of P (A) is 0.4286.

(2) The value of P (B) is 0.50.

(3) The value of P (A ∩ B) is 0.2143.

(4) The the value of P (B|A) is 0.50.

(5) The events <em>A</em> and <em>B</em> are independent.

Step-by-step explanation:

The events are defined as follows:

<em>A</em> = a student in the class has a sister

<em>B</em> = a student has a brother

The information provided is:

<em>N</em> = 210

n (A) = 90

n (B) = 105

n (A ∩ B) = 45

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The conditional probability of an event <em>X</em> provided that another event <em>Y</em> has already occurred is:

P(X|Y)=\frac{P(A\cap Y)}{P(Y)}

If the events <em>X</em> and <em>Y</em> are independent then,

P(X|Y)=P(X)

(1)

Compute the probability of event <em>A</em> as follows:

P(A)=\frac{n(A)}{N}\\\\=\frac{90}{210}\\\\=0.4286

The value of P (A) is 0.4286.

(2)

Compute the probability of event <em>B</em> as follows:

P(B)=\frac{n(B)}{N}\\\\=\frac{105}{210}\\\\=0.50

The value of P (B) is 0.50.

(3)

Compute the probability of event <em>A</em> and <em>B</em> as follows:

P(A\cap B)=\frac{n(A\cap B)}{N}\\\\=\frac{45}{210}\\\\=0.2143

The value of P (A ∩ B) is 0.2143.

(4)

Compute the probability of <em>B</em> given <em>A</em> as follows:

P(B|A)=\frac{P(A\cap B)}{P(A)}\\\\=\frac{0.2143}{0.4286}\\\\=0.50

The the value of P (B|A) is 0.50.

(5)

The value of P (B|A) = 0.50 = P (B).

Thus, the events <em>A</em> and <em>B</em> are independent.

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