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zubka84 [21]
3 years ago
15

What two values the following number 250 is between

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Joyce wants to mix granola and raisins together to make a snack for her class. Granola costs $2 per pound and raisins cost $4.50
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Need help ASAP, will mark brainliest if you can check my answer:
ki77a [65]

According to the <em>compound interest</em> model, we find the following results: I) x ≈ 11.5 yr, C' = $ 101317.36, II) r ≈ 7.4 %, x ≈ 9.8 yr, III) C = $ 7626.38, x ≈ 8.6 yr, IV) r ≈ 6.5 %, C = $ 12801.61

<h3>How to determined all the variables associated with compound interest</h3>

<em>Compound</em> interest describes the <em>capital</em> gain in term of <em>deposited</em> capital and the consideration that such capital is increased continuously in time. The compound interest model is shown below:

C' = C · (1 + r/100)ˣ     (1)

Where:

  • C - Initial capital
  • C' - Current capital
  • r - Interest rate, in percentage.
  • t - Time, in years

The <em>doubling</em> time (x) is the period needed for a capital to be doubled. It is described by the following expression based on (1):

x = (㏒ 2)/[㏒ (1 + r/100)]     (2)

Now we proceed to calculate each missing variable:

Case I - Doubling time

x = (㏒ 2)/[㏒ (1 + 6.2/100)]

x ≈ 11.5

Case I - Current capital

C' = 75000 · (1 + 6.2/100)⁵

C' = 101317.36

Case II - Interest rate

r = 100\cdot \left(\sqrt [5] {\frac{7130.90}{5000} }-1\right)

r ≈ 7.4

Case II - Doubling time

x = (㏒ 2)/[㏒ (1 + 7.3/100)]

x ≈ 9.8

Case III - Initial capital

C = 11414.71/(1 + 8.4/100)⁵

C = 7626.38

Case III - Doubling time

x = (㏒ 2)/[㏒ (1 + 8.4/100)]

x ≈ 8.6

Case IV - Interest rate

r = 100\cdot \left(\sqrt [11] {2 }-1\right)

r ≈ 6.5

Case IV - Initial capital

C = 17539.32/(1 + 6.5/100)⁵

C = 12801.61

To learn more on compound interest: brainly.com/question/14295570

#SPJ1

3 0
2 years ago
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