3 years ago

F(x)=-x^2-5 find the range

1 answer:

lina2011 [118]3 years ago

4 0

$x = \frac{ - b}{2a} \\ = \frac{0}{2(1)} = 0 \\ f(0) = (0)^{2} - 5 \\ = 0 - 5 = - 5$
The vertex is at (0,-5), therefore the range goes from (-infinity, - 5]

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This is Algebra 2. help me

gladu [14]

(4x^2-25)/(2x-5)=14
we hates fractions so m ultiply both sides by (2x-5)
4x^2-25=14(2x-5)
4x^2-25=28x-70
add 70 to both sides
4x^2+45=28x
subtract 28x fromoth sides
4x^2-28x+45=0
use quadratic formula which is
if you have
ax^2+bx+c=0 then
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a} 
$
a=4
b=-28
c=45
subsitute
x= $\frac{-(-28)+/- \sqrt{(-28)^{2}-4(4)(45)} }{2(4)} 
$
x= $\frac{28+/- \sqrt{784-720} }{8} 
$
x= $\frac{28+/- 8}{8} 
$
x= $\frac{5}{2} 
$ or $\frac{9}{2} 
$
if we were to put 5/2 for x, the deonomentor would be equal to zero, so it cannot be used

answer is
x=9/2

3 0

3 years ago

In a row of boys facing north , A is fifteen from the left and C is fifteen from the right. B who is fifth from the right of A i

ANTONII [103]

Reading the question and adding everything up you'll get (15+3+1+1+4+1+15)

Which gets us our answer of 40 boys.

Hope I helped you.

4 0

3 years ago

Option 1: $4000 at 3% interest for 6 years

irakobra [83]

Answer:

The man right there is wrong. It is Option 3 .......

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