Question

F(x)=-x^2-5 find the range

Answer 1

$x = \frac{ - b}{2a} \\ = \frac{0}{2(1)} = 0 \\ f(0) = (0)^{2} - 5 \\ = 0 - 5 = - 5$
The vertex is at (0,-5), therefore the range goes from (-infinity, - 5]