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Ber [7]
3 years ago
8

F(x)=-x^2-5 find the range

Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

x =  \frac{ - b}{2a}  \\  =   \frac{0}{2(1)}  = 0 \\ f(0) = (0)^{2}  - 5 \\  = 0 - 5 =  - 5
The vertex is at (0,-5), therefore the range goes from (-infinity, - 5]
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Step-by-step explanation:

some rules of logarithmic function

ln(a) - ln(b)=ln(\frac{a}{b})

e^{ln(a)}=a

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Use the 3rd rule in the 1st term

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3 0
3 years ago
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Answer:

-31/8. That's the answer to your question

3 0
3 years ago
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