The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Let's consider adults tickets be a and child tickets be c
so
Roy's purchase
6a+2c=66------1
Elisa's purchase
5a+4c=62-------2
Hence, the system of equations
6a+2c=66------1
5a+4c=62-------2
solving simultaneously
6a+2c=66
5a+4c=62
Also,
12a+4c=132
-5a+4c=62
7a=70
a=$10
put a=70 in 1
6(10)+2c=66
60+2c=66
2c=66-60
2c=6
c=$3
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we know that
Quotient is the number resulting from the division of one quantity by another
Let
x--------> the first quantity
y------> the second quantity
q------> the quotient
So
-------> equation 1
in this problem

Substitute the values in the equation 1

Simplify

therefore
<u>the answer is</u>
The quotient is equal to 
The equation would be x+15=46. I came up with this equation because we are given the total number of people at the reunion this year and we know how many more people are here this year than last year. The unknown is the number of people last year. That is why x would represent the number of people at the reunion last year because that is the unknown. If we add 15 to the number of people last year, it will give us 46( the number of people at the reunion this year).
To find x, we just use opposite operation to get the answer. Opposite of addition is subtraction so, we subtract the number of more people and the reunion this year from the total number of people at the reunion to get the unknown number of people at the reunion last year. 46-15 is 31. Therefore we know that 31 people were at the reunion last year