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Virty [35]
3 years ago
12

Solve for d 1.2+d+0.4=9.7

Mathematics
1 answer:
mote1985 [20]3 years ago
5 0
1.2+d+0.4=9.7
1.6+d=9.7
-1.6. -1.6

D=8.1
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A coin is weighted so that the probability of getting heads is 0.70. If the coin is flipped twice, what is the probability of ge
Naily [24]
If the probability of flipping heads is 0.70, the probability of flipping tails is 0.30. 

To find probability, you multiply the probability of each factor together:

P = 0.7  * 0.3 

P = 0.21 <em>or</em>
<em> </em>21%
3 0
3 years ago
Please help me with this!
Igoryamba

Answer:

1: 39,284

2: 58,672.8

3: 2,066.79153912

4: 183.801664976

5: 8,744,119.16410

Those are the answers to the problems now you can just determine which ones are from least to greatest

7 0
3 years ago
Read 2 more answers
a stack of cards is placed next to a ruler, and the height of stack measured to be 3/4inches. how thick is one card
4vir4ik [10]

Total thickness of the stack of cards = 3/4 inch or 0.75 inch

In a full stack of cards, there are 52 cards.

Hence, the thickness of 52 cards = 0.75 inch.

To find the thickness of one card, we divide the total thickness with the total number of cards.

Thickness of one card = \frac{0.75}{52} = 0.014423 inch

1 inch = 2.54 cm

0.014423 inch is approximately equal to 0.34 cm.

Answer = 0.34 cm

7 0
3 years ago
Simplify the expression below. 3c - 2cd - 8c + 7d
jolli1 [7]
<span>3c - 2cd - 8c + 7d
= -5c </span> - 2cd + 7d

hope it helps
3 0
4 years ago
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
2 years ago
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