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JulsSmile [24]
3 years ago
5

Using the equation of the line (y = 0.5x + 79), what would be the melting point of dna with 50% gc content? enter your answer as

a whole number

Mathematics
2 answers:
olga_2 [115]3 years ago
5 0

The melting point of DNA with 50% GC content = 104 °C

<h3>Further explanation</h3>

DNA has a base pair of bonds between adenine and thymine and guanine and cytosine. These bonds are hydrogen bonds.

Three hydrogen bonds between guanine-cytosine and two hydrogen bonds adenine-thymine make denaturation of DNA by heating it requires greater heat energy.

The amount of guanine and cytosine in the DNA molecule (the GC content) is directly proportional to the melting point, the temperature at which DNA is denatured

If we plot between the melting point of DNA (y-axis) and the percentage of the GC content (x-axis) we will get a straight line equation

From the equation of the line (y = 0.5x + 79), with GC content 50%, we enter the GC value as x so we get the DNA melting point as y

y = 0.5.50 + 79

y = 104 °C

<h3>Learn more</h3>

the part of the DNA molecule

brainly.com/question/3082790

the rungs of the ladder structure of DNA

brainly.com/question/1619893

the structure of a nucleotide DNA and an RNA nucleotide.

brainly.com/question/6460381

the antiparallel arrangement of DNA strands

brainly.com/question/1601535

Keywords: GC content, DNA structure, melting point, hydrogen bonds, adenine, thymine, guanine, cytosine, denaturation

steposvetlana [31]3 years ago
4 0
We have the equation of the line as follows:
y = 0.5x + 79

We want to calculate the melting point (the y value) of DNA  with 50% gc content (the x value).
The gc content represents the value of x in the equation, so to calculate the melting point (y), we will simply substitute the x with 50 in the equation of the line as follows:
melting point = 0.5(50) + 79 = 25 + 79 = 104 degrees
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Step-by-step explanation:

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In a city known for many tech start-ups, 311 of 800 randomly selected college graduates with outstanding student loans currently
Allushta [10]

Answer:

Null hypothesis:p_{1} - p_{2}=0  

Alternative hypothesis:p_{1} - p_{2} \neq 0  

z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)(\frac{1}{800}+\frac{1}{800})}}=-1.182    

p_v =2*P(Z  

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.  

Step-by-step explanation:

1) Data given and notation  

X_{1}=311 represent the number college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

X_{2}=334 represent the number college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

n_{1}=800 sample 1

n_{2}=800 sample 2

p_{1}=\frac{311}{800}=0.389 represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

p_{2}=\frac{334}{800}=0.418 represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if is there is a difference in the two proportions, the system of hypothesis would be:  

Null hypothesis:p_{1} - p_{2}=0  

Alternative hypothesis:p_{1} - p_{2} \neq 0  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{311+334}{800+800}=0.403  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)(\frac{1}{800}+\frac{1}{800})}}=-1.182    

4) Statistical decision

Since is a two sided test the p value would be:  

p_v =2*P(Z  

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.  

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Answer:

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Step-by-step explanation:

We have been given the freezing temperatures of cottonseed oil and coconut oil. The freezing temperature of cottonseed oil is -48.1 degree celsius and the same for coconut oil is 24.8 degree celsius.

We are supposed to compare the two freezing temperatures. We know that 24.8 is higher than -48.1, therefore, we can conclude that freezing temperature of coconut oil is higher than the freezing temperature of cottonseed oil because 24.8 is more than -48.1. Thus, correct answer is option (C).

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