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Mademuasel [1]
2 years ago
14

A cyclist travels 3 miles in 15 minutes and then a further 7 miles in 25 minutes without stopping.

Mathematics
1 answer:
Oduvanchick [21]2 years ago
5 0

Answer:

v = 15 mph

Step-by-step explanation:

Given that,

A cyclist travels 3 miles in 15 minutes and then a further 7 miles in 25 minutes without stopping.

Total distance, d = 3 + 7 = 10 miles

Total time, t = 15 + 25 = 40 minutes = 0.6667 hours

Average speed,

v=\dfrac{d}{t}

Put all the value,

v=\dfrac{10}{0.6667}\\\\= $$14.99\ mph

or

v = 15 mph

So, the required average speed is equal to 15 mph.

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Find the unknown measure of the rectangle.<br> Area =28 square centimeters <br>Height =?
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A = 28  so 28 = 4 * height
height  = 28/4 = 7
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The height of a right triangle is √6 units and the base is √9 units. Find the area of the triangle
In-s [12.5K]

Answer:

Step-by-step explanation:

h = √6 units

b = √9 units

A = b*h/2 = √6·√9 /2 = √(6·9)/2 = √(2·3·3·3)/2 = 3√3 /2 units ²≈ 2.6 units²

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2 years ago
Find the mean median mode and range for the following data 77 60 59 70 89 95
Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

  • 77,60,59,70,89,95

Sort:

  • 59,60,70,77,89,95

To find:

  • Mean
  • Median
  • Mode
  • Range

Mean:

\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}

Sum of all data divides by amount.

\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:

\displaystyle \large{\dfrac{x_1+x_2}{2}}

From 59,60,70,77,89,95, since 70 and 77 are in middle:

\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

\displaystyle \large{x_{max}-x_{min}} or highest value - lowest value

Thus:

\displaystyle \large{95-59 = 36}

Therefore, range = 36

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2 years ago
Each train car holds 71 passengers. About how many train cars
gulaghasi [49]

567/71 because passengers/(train cars/passengers) = train cars

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