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musickatia [10]
3 years ago
8

A table top is made of circular glass what is the circumference of the table if it has a radius of 21 cm?

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

Answer:

131.95cm

Step-by-step explanation:

Circumference of a circle is 2 × pi × r

= 2 × pi × 21

= 131.95 cm

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The future value of a certain money market account with a fixed interest rate of
rosijanka [135]

Answer:

D = $8637.45

Step-by-step explanation:

Rate = 3.65% = 0.0365

Principal = 5000

Time (t) = 15 years

N = 12 (since its compounded monthly)

Compound interest (A) = P(1 + r/n)^nt

A = 5000(1 + 0.0365 / 12)^15*12

A = 5000(1 + 0.00304)¹⁸⁰

A = 5000(1.00304)¹⁸⁰

A = 5000 * 1.7269

A = 8634.86

The investment would worth $8634.86

Note: the final answer may vary slightly from the answer in the options due to ± from approximation

3 0
3 years ago
Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

lim(u→0) (sin(π(u + 2)) + 8 − (u + 2)³) / ((u + 2) − 2)

lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
3 years ago
Please help is and example of ?
Helen [10]
I believe that it is B. Hope this helps!
5 0
3 years ago
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Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)
melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

f_x = \dfrac{x^2}{a^7-x^7}

= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}

= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}

since  \Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)

Then, it implies that:

\implies  \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}

\mathbf{=  \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}

7 0
2 years ago
Which of the following pairs show two congruent triangles?
Dvinal [7]

Answer:

B and C

Step-by-step explanation:

They're congruent

4 0
3 years ago
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