Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Let the weightage of Ease of Use be x
Ease of Use = x
<span>Compatibility is 5 times more than ease of use:
</span>Compatibility = 5x
<span>Reputation is 3 times more important than compatibility:
</span>Reputation = 3(5x)
Reputation = 15x
<span>Cost is 2 times more important than reputation:
</span>Cost = 2(15x)
Cost = 30x
So the weightage are:
Ease of Use : 1
Compatibility : 5
Reputation :15
Cost : 30
Answer: Amount of 35% solution required = 100 milliliters
Amount of 87% solution required = 30 milliliters
Step-by-step explanation:
Given: Total solution required = 130 milliliters
Let x = Amount of 35% solution (in milliliters).
Then, Amount of 87% solution required = 130 - x
As per given,
Concentration = 0.35x +0.87(130-x)=0.47(130)
Hence, Amount of 35% solution required = 100 milliliters
Amount of 87% solution required = 130-100 milliliters =30 milliliters
Answer:
x= -3/4 or -0.75
Step-by-step explanation:
1) subtract 7 from both sides which would make it
-3x= 5x+6
2) Subtract 5x from both sides which would make it
-8x-6
3) Divide both sides by -8
which gives you -3/4
Answer:
0=4+27
Step-by-step explanation:
