Answer:
Step-by-step explanation:
cot(theta) = 1 / tan(theta)
cot(theta) = 1 / -5
cot(theta) = - 0.2
Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Answer:
7/1 or 7
Step-by-step explanation:
because you rise (vertically) seven and run (horizontally) 1, so 7/1 but simplified it's just 7 so either is valid.
Answer: 49 cm^2
Step-by-step explanation:
The length of the small pink square box will be:
L^2 = 9
L = sqrt( 9 )
L = 3
The length of the big pink square box will be:
L^2 = 16
L = sqrt( 16 )
L = 4
The length of the yellow square box will be:
4 + 3 = 7
The area of the third square box will be
A = 7^2
A = 49 cm^2