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3 years ago

Please help, I don’t need an explanation, just the answer.

Mathematics

1 answer:

ahrayia [7]3 years ago

7 0

Answer:

x=2 y=4

Step-by-step explanation:

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Plz help will make the Brainly

marysya [2.9K]

Answer:

-2

Step-by-step explanation:

Two points (1,0) (0,2) use slope formula 0-2/1-0

8 0

3 years ago

Lines d, e, and f are parallel. That means they have the same slope. Each of these lines has a slope of −3. Enter numbers to com

Sloan [31]

Answer:

Line d : y = -3x - 3

Line e : y = -3x - 2

Line f : y= -3x + 2

Step-by-step explanation:

Given that,

The slope of each line is -3.

Now,

We know that,

Equation of line is represented by y = mx + c

where m is the slope and c is the y-intercept.

Now,

Given that,

Line d goes through (0, - 3) and (- 1, 0).

So,

y-intercept of Line d is -3

∴ we get

Equation of Line d is : y = -3x -3

Now,

Given that,

Line e goes through (-1, 2) and (0, -2).

So,

y-intercept of Line e is -2

∴ we get

Equation of Line e is : y = -3x - 2

Now,

Given that,

Line f goes through (0, 2) and (1, -1).

So,

y-intercept of Line e is 2

∴ we get

Equation of Line f is : y = -3x + 2

6 0

3 years ago

I need help..... I don't understand at all

cluponka [151]

I think you have to estimate to a whole so 2 1/2 would be 3

8 0

3 years ago

Read 2 more answers

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

3 years ago

Let f(x) =x+1 and g(x)=1/x. The graph of (f o g)(x) is shown below. What is the range of (f o g)(x)?

sveta [45]

Looks like all real numbers except 1. It touch's all the y except 1 aka range

6 0

3 years ago

Read 2 more answers