Answer:
The area of one trapezoidal face of the figure is 2 square inches
Step-by-step explanation:
<u><em>The complete question is</em></u>
The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?
we know that
The area of a trapezoid is given by the formula
where
b_1 and b-2 are the parallel sides
h is the height of the trapezoid (perpendicular distance between the parallel sides)
we have
substitute the given values in the formula
Answer:
(n- 2/3)²
Step-by-step explanation:
- <em>Perfect square trinomial is: </em><em>a²+2ab+b²= (a+b)²</em>
We have:
It can be put as:
Here we consider n = a and -2/3 = b, then
Now we add 4/9 to a given binomial to make it perfect square:
- n² - 2×n×3/2 + 4/9= (n- 2/3)²
So, added 4/9 and got a perfect square (n- 2/3)²
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
Answer:
.125
Step-by-step explanation:
The volume of a cube is found by
V = s^3 where s is the side length
V = .5 ^3
V =.125 m^3
56 57 and 58 are the three numbers that work
