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3 years ago

I need help..... I don't understand at all

Mathematics

2 answers:

cluponka [151]3 years ago

8 0

I think you have to estimate to a whole so 2 1/2 would be 3

zloy xaker [14]3 years ago

4 0

You will have to estimate the two fraction by the benchmark which is 0,1/2, or 1 then add the fraction that you estimate with the mixed number beside it. Add the to number together to get the answer.

Example:
3 2/3 - 1 1/2

3 2/3 = 4
1 1/2 = 1 1/2
4 - 1 1/2 = 2 1/2

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X² - x - 6 = 0 Solutions?

Ira Lisetskai [31]

Factors of -6 that add up to -1:

(x - 3)(x + 2)

Set them to 0 and solve for x

x = 3 

x = -2

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3 years ago

Which expression is equivalent to 4(x+2)? 6x 4(x)+4(2) 4x)+4 8x

vlada-n [284]

The expression that is equivalent to 4(x+2) is 4(x)+4(2)

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3 years ago

Read 2 more answers

I need help on how to solve this and what the answer is

stiks02 [169]

On your calculator do 4/3 x pi (approx 3.14) x 4^3
so 4/3 x pi x 64
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3 0

3 years ago

Use The function f(x) is graphed below. the graph of the function to find, f(6).

____ [38]

F(6)=2

That is because the 6 in the brackets means x
If f(x) means f(6) x=6

And if you look at the graph where the 6 on the x axis is and look where the graph meets the value of 6 it is on the value of 2 on the y axis

4 0

4 years ago

Read 2 more answers

"6. A brand name has a 40% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small s

statuscvo [17]

Answer:

(a) The probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b) The probability that all of the selected consumers recognize the brand name is 0.0041.

(d) The events of 5 customers recognizing the brand name is unusual.

Step-by-step explanation:

Let X = number of consumer's who recognize the brand.

The probability of the random variable X is, P (X) = p = 0.40.

A random sample of size, n = 6 consumers are selected.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the value of P (X = 5) as follows:

$P(X=5)={6\choose 5}0.40^{5}(1-0.40)^{6-5}\\=6\times0.01024\times0.60\\=0.036864\\\approx0.0369$

Thus, the probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b)

Compute the value of P (X = 6) as follows:

$P(X=6)={6\choose 6}0.40^{6}(1-0.40)^{6-6}\\=1\times 0.004096\times1\\=0.004096\\\approx0.0041$

Thus, the probability that all of the selected consumers recognize the brand name is 0.0041.

(c)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = P (X = 5) + P (X = 6)

= 0.0369 + 0.0041

= 0.041

Thus, the probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d)

An event is considered unusual if the probability of its occurrence is less than 0.05.

The probability of 5 customers recognizing the brand name is 0.0369.

This probability value is less than 0.05.

Thus, the events of 5 customers recognizing the brand name is unusual.

8 0

4 years ago