2 years ago

A rectangle has side measurements of 12 units and 8 units.

Mathematics

1 answer:

marusya05 [52]2 years ago

7 0

D=√w^2+l^2
d=√8^2+12^2
d=√64+144
d≈14.4

You might be interested in

How to represent fracctions on a line

krek1111 [17]

You know the lines on a number line those can be fractions

6 0

3 years ago

Find the following when a = -3, b = 6, c = −4/5 9b−72a+1

Vadim26 [7]

271.

Hope this helped!

8 0

3 years ago

Answer as soon as possible, please and thank you. All help is truly appreciated because we are one step closer to the answer. Be

SpyIntel [72]

Answer: 100

Step-by-step explanation:

4b squared where b= 5

Slot in 5 for b; 5 squared = 5x5= 25

4 (25)

=100

7 0

3 years ago

Read 2 more answers

Cosx = 1/2 tan X = 0 solve

Reil [10]

Step-by-step explanation:

see the answer in the pic

4 0

2 years ago

Read 2 more answers

Two litters of a particular rodent species have been born; first with two brownhaired and one gray-haired (litter 1) and the oth

maks197457 [2]

Answer:

The probability that the animal chosen is brown-haired is 0.6333.

Step-by-step explanation:

Denote the events as follows:

A : a brown-haired rodent

B : Litter 1

The information provided is:

$P (A|B) =\frac{2}{3}\\\\P(A|B^{c})=\frac{3}{5}$

The probability of selecting any of the two litters is equal, i.e.

$P(B)=P(B^{c})=\frac{1}{2}$

According to the law of total probability:

$P(X)=P(X|Y_{1})P(Y_{1})+P(X|Y_{2})P(Y_{2})+...+P(X|Y_{n})P(Y_{n})$

Compute the total probability of event A as follows:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

$=[\frac{2}{3}\times\frac{1}{2}]+[\frac{3}{5}\times\frac{1}{2}]\\\\=\frac{1}{3}+\frac{3}{10}\\\\=\frac{10+9}{30}\\\\=\frac{19}{30}\\\\=0.6333$

Thus, the probability that the animal chosen is brown-haired is 0.6333.

5 0

3 years ago