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Lynna [10]
3 years ago
11

If 5+ 20 -22-3х - 10.2-2x+5, what is the value of х?

Mathematics
1 answer:
Elodia [21]3 years ago
8 0

Answer:

<h2>3</h2>

Step-by-step explanation:

5+20\cdot2^{2-3x}=10\cdot2^{-2x}+5\qquad\text{subtract 5 from both sides}\\\\20\cdot2^{2-3x}=10\cdot2^{-2x}\qquad\text{divide both sides by 10}\\\\2\cdot2^{2-3x}=2^{-2x}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\2^{1+2-3x}=2^{-2x}\\\\2^{3-3x}=2^{-2x}\iff3-3x=-2x\qquad\text{subteact 3 from both sides}\\\\-3x=-2x-3\qquad\tex\qquad\text{add}\ 2x\ \text{to both sides}\\\\-x=-3\qquad\text{change the signs}\\\\x=3

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4.7 kg = __<br><br><br><br><br><br> What equals 4.7 kg =____g
Flauer [41]

Answer:

If your asking what 4.7kg is to grams then it is 4700g

5 0
3 years ago
Read 2 more answers
Find an equation of the line passing through the pair of points. Write the equation in slope-intercept form. (2,8), and (8,2)
leonid [27]

Answer:

y=-x+10

Step-by-step explanation:

Hi there!

Slope intercept form: y=mx+b where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)

<u>1) Find the slope (m)</u>

m=\frac{y_2-y_1}{x_2-x_1} where the two given points are (x_1,y_1) and (x_2,y_2)

Plug in the given points (2,8),and (8,2)

​m=\frac{2-8}{8-2}\\m=\frac{-6}{6}\\m=-1

Therefore, the slope of the line is -1. Plug this into  y=mx+b:

y=-x+b

<u>2) Find the y-intercept (b)</u>

y=-x+b

Plug in a given point and solve for b

8=-2+b

Add 2 to both sides

8+2=-2+b+2\\10=b

Therefore, the y-intercept is 10. Plug this back into y=-x+b:

y=-x+10

I hope this helps!

3 0
3 years ago
12:53:34
Drupady [299]

Answer:

Reference Point

Step-by-step explanation:

The answer is reference point. This is because reference point is used to determine if an object is in motion or if it has changed is direction.

Thus, reference point has to be a value of zero for us to use it to determine if an object has moved.

8 0
3 years ago
Let −→ ab= h2, −3, −1i. if the coordinates of a are (2, −1, 5), what are the coordinates of the point b?
Over [174]
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4 years ago
Find the surface area of a pyramid with a square base with dimensions 100 mm by 100 mm and height of 75 mm.
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To solve for the surface area of the pyramid, we make use of the formula:

A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))

where,

l and w are the base of the pyramid = 100 mm

h is the height of the pyramid = 75 mm

 

Substituting the given values into the equation:

A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100 / 2)^2 + 75^2))

A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)

A = 20,148.90 mm^2

 

Therefore the surface area of the pyramid is about 20,149 mm^2.

8 0
3 years ago
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