What is the domain of the following list of ordered pairs (-4,-2) (3,5,(0,4)

Alexei wants to hang a mirror in his boat and put a frame around it. The mirror and frame must have an area of 19.25 square feet

zhuklara [117]

Let

x---------> the thickness of the frame in feet

At-------> Area of the mirror and the frame in square feet

we know that

$At=19.25ft^{2}$ ------> equation $1$

$At=(3+2x)*(5+2x)\\ At=3*5+3*2x+5*2x+2x*2x\\ At=15+6x+10x+4x^{2} \\ At=4x^{2} +16x+15$ --------> equation $2$

equate equation $1$ and equation $2$

$19.25=4x^{2} +16x+15\\ 4x^{2} +16x+15-19.25=0\\ 4x^{2} +16x-4.25=0$

therefore

the answer is the option

$C. 4x2 + 16x - 4.25 = 0$

5 0

3 years ago

Read 2 more answers

-2/3p - 4 < 8<br><br>help for 15 points.

wel

Answer:

p > -18

Step-by-step explanation:

-2/3p - 4 < 8

-2/3p < 12

p > 12 x -3/2

p > -18

3 0

2 years ago

Read 2 more answers

Which one is it please tell me quick

natulia [17]

Answer:

I'm sorry I just need points!

Step-by-step explanation:

5 0

2 years ago

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

Verdich [7]

Answer:

72 kg

Step-by-step explanation:

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

We are given the ratio

cement: sand:stones

= 1:2:4

The sum of proportion =

1 + 2 + 4 = 7

We are given the kg of sand = 144kg

Step 1

We find the total kg of cement, sand and stones = x

Using the proportion of sand,

2/7 of x = 144kg

2/7 × x = 144kg

2x/7 = 144kg

Cross Multiply

2x = 7 × 144kg

x = 7 × 144kg/2

x = 504kg

Therefore the total kg of cement, sand and stone = 504kg

Step 2

The amount of cement required is calculated as:

1/7 × 504 kg = 72 kg

Therefore, 72kg of cement is required.

4 0

3 years ago

In a recent contest, the mean score was 210 and the standard deviation was 25. a) Find the z-score of John who scored 190 b) Fin

denpristay [2]

Answer:

a) $Z = -0.8$

b) $Z = 2.4$

c) Mary's score was 241.25.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 210, \sigma = 25$