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Elena-2011 [213]
3 years ago
9

A typical adult has an average IQ score of 105 with a standard deviation of 20. If 20 randomly selected adults are given an IQ t

est, what is the probability that the sample mean scores will between 102 and 110 points? (Round to 2 decimal places)
Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer: 0.55

Step-by-step explanation:

Given :

A typical adult has an average IQ score of n \mu=105 with a standard deviation \sigma=20.

Sample size : n= 20

Let x represents the IQ score of adults.

The probability that the sample mean scores will between 102 and 110 points will be :-

P(102

Therefore, the probability that the sample mean scores will between 102 and 110 points = 0.55

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What is the value of x in the equation 5x+3 - 4x?
Dafna1 [17]

5x + 3 - 4x = 0

x + 3 = 0

x = -3

Hope this helps :)

6 0
4 years ago
Subtract. 5x^2-5x+1-(2x^2+9x-6)
Talja [164]
<h2>Hello!</h2>

The answer is:

3x^{2} -14x+7

<h2>Why?</h2>

To solve the problem we need to add/subtract like terms. We need to remember that like terms are the terms that share the same variable and the same exponent.

For example, we have:

x^{2} +2x+3x=x^{2} +(2x+3x)=x^{2}+5x

We have that we were able to add just the terms that were sharing the same variable and exponenr (x for this case).

So, we are given the expression:

5x^2-5x+1-(2x^2+9x-6)=5x^{2}-2x^{2}-5x-9x+1-(-6)\\\\(5x^{2}-2x^{2})+(-5x-9x)+(1-(-6))=3x^{2}-14x+7

Hence, the answer is:

3x^{2} -14x+7

Have a nice day!

4 0
3 years ago
(y+3) solve by using the distributive property ​
MA_775_DIABLO [31]

Answer:

y-3

Step-by-step explanation:

4 0
3 years ago
A) There are 100 students who play at least one of volleyball, soccer and hockey, of these 50 play au three games, 84 play socce
Scilla [17]

Answer:

<h2>i) 3</h2><h2>ii) 5</h2>

Step-by-step explanation:

Let H be the set of students who play Hokey

     V be the set of students who play Volleyball

     S be the set of students who play Soccer

======================================

card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]

                                 = 73 - [50 + (58-50) + (62-50)]

                                 = 73 - [50 + 8 + 12]

                                 = 73 - 70

                                 = 3

………………………………………………

Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]

                              = 100 - 95

                              = 5

…………………

<u><em>Note</em></u> :

A Venn diagram might be helpful in such case.

5 0
2 years ago
Last week Kellie ran 28 miles this week she ran 32 miles what was the percent change in the number of miles she ran
wel
Kelli ran 4 more miles than the week before, so to find what percent that is of 28, divide.

4 / 28 = 0.142857143, or ~14.29%

Kelli ran 14.2857143% or about 14.29% more miles than last week.
8 0
3 years ago
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