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3 years ago

Multiply and simplify (x+1)^3x(x+1)^4

Mathematics

1 answer:

Ber [7]3 years ago

8 0

multiply (x+1)^3 × (x+1)^4

As , the bases are same so we can add up the exponents

so the answer is (x+1)^3+4

that means (x+1)^7

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Question 2 (1 point)

KIM [24]

Answer:

first week = m miles

second week = 6 miles less than triple the number of miles they ran the

first week.

Triple of the number of miles they ran the first week = 3 * m = 3m

Therefore = 3m - 6

3 0

3 years ago

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Misha Larkins [42]

What are you supposed to solve???

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2 years ago

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A bag contains 20 marbles. The probability of picking a yellow marble is 3/4. How many marbles are yellow?

emmasim [6.3K]

15 because 3/4 is equivalent to 75% and 75% of 20 is 15.

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3 years ago

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Write a equation of a hyperbola given the foci and the asymptotes

professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

$\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}$

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}$

The asymptote of n hyperbola is expressed as

$y=\pm\frac{a}{b}(x-h)+k$

Given that the asymptotes are

$y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x$

This implies that

$a=3,\text{ and b=4}$

To evaluate the value of h and k,

$undefined$

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1 year ago

20 points I beg you help

svp [43]

Answer : -6

The common difference of a sequence is the value that changes every time the sequence continues.

In your sequence it is seen that 6 is subtracted from each term in order to get to the next in the sequence.

7 0

2 years ago

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