Answer:
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Step-by-step explanation:
usernane is william_12365
Substitute
![u=\ln x](https://tex.z-dn.net/?f=u%3D%5Cln%20x)
, so that
![\mathrm du=\dfrac{\mathrm dx}x](https://tex.z-dn.net/?f=%5Cmathrm%20du%3D%5Cdfrac%7B%5Cmathrm%20dx%7Dx)
. The integral is then equivalent to
![\displaystyle\int\frac{\mathrm dx}{x\ln^px}=\int\frac{\mathrm du}{u^p}=\begin{cases}\dfrac{u^{p+1}}{p+1}+C&\text{for }p\neq1\\\\\ln|u|+C&\text{for }p=1\end{cases}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5Cfrac%7B%5Cmathrm%20dx%7D%7Bx%5Cln%5Epx%7D%3D%5Cint%5Cfrac%7B%5Cmathrm%20du%7D%7Bu%5Ep%7D%3D%5Cbegin%7Bcases%7D%5Cdfrac%7Bu%5E%7Bp%2B1%7D%7D%7Bp%2B1%7D%2BC%26%5Ctext%7Bfor%20%7Dp%5Cneq1%5C%5C%5C%5C%5Cln%7Cu%7C%2BC%26%5Ctext%7Bfor%20%7Dp%3D1%5Cend%7Bcases%7D)
Then transforming back to
![x](https://tex.z-dn.net/?f=x)
gives
<h2><u>Given</u></h2>
![- 5c + 9c = - 20](https://tex.z-dn.net/?f=%20-%205c%20%2B%209c%20%3D%20%20-%2020)
<h2><u>To </u><u>Find</u></h2>
Value of c term
<h2><u>Solution</u></h2>
![- 5 + 9c = - 20 \\ \\ = > 4c = - 20 \\ \\ = > c = \frac{ - 20}{4} \\ \\ = > c = \cancel \frac{ - 20}{4} \\ \\ = > c = - 5](https://tex.z-dn.net/?f=%20-%205%20%2B%209c%20%3D%20%20-%2020%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%204c%20%3D%20%20-%2020%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20c%20%3D%20%20%5Cfrac%7B%20-%2020%7D%7B4%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20c%20%3D%20%5Ccancel%20%5Cfrac%7B%20-%2020%7D%7B4%7D%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%3E%20c%20%3D%20%20-%205)
<h3>Hope This Helps</h3>
Answer:
Step-by-step explanation:
Half of the 16 oz = 8 oz of peanuts.
2 oz are almonds.
1 oz is cashews.
3 oz are raisins.
So, we know 8+2+1+3 = 14 oz of stuff in detail.
We're told the rest is chocolate chips, which means 16 - 14 = 2 oz.
BUT always read the question.
It does not ask the weight of the chocolate chips. It asks the fraction.
That is
2/16 = 1/8
Answer:
The number of letters in the one street be 220 .
Step-by-step explanation:
As given
A postman has to deliver 450 letters .
The number of letters delivered in one street is twice the number delivered in other .
Let us assume that the number of letters delivered in second street be x.
Let us assume that the number of letters delivered in first street = 2x
As given
If he is left with 120 letters .
Thus
The number of letter delivered in one and other street = 450 - 120
= 330
Than the equation becomes
x + 2x = 330
3x = 330
![x = \frac{330}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B330%7D%7B3%7D)
x = 110
The number of letters in the one street = 2 × 110
= 220
Therefore the number of letters delivered in first street be 220.