Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
32.4kg
Step-by-step explanation:
if it loses one tenth of cement;
36kg×1/10
36kg/10
3.6kg was lost
to find the remaining ; 36kg - 3.6kg = 32.4kg is left in the bag
Answer: It would be x^2 I think
Answer:
H2=02+A2
H2=9+16
=25
Step-by-step explanation:
sino =0/H
3/5
