Answer:
a b
Step-by-step explanation:
I think it is a and b if am not wrong good luck
First time the area of the circle and the square.
The radius of the first is 4, so the area of the circle is 16pi.
The area of the square is 32.
You can subtract the area of the circle by the square because some most of the circle is being covered by the square.
16pi-32 is the area of the circle that is visible.
16pi-32:32 can be simplified to pi-2:2
So the probability that a randomly selected point within the circle falls in the white area is
pi-2:2 or in decimal terms, ≈1.14:2
9514 1404 393
Answer:
11 cm by 33 cm
Step-by-step explanation:
You can solve this problem mentally as follows.
Consider the rectangle as 3 squares, side-by-side. Then the area of each of those squares is 363/3 = 121 cm^2. From your knowledge of the squares of numbers, you know that 121 = 11^2. So, the width of the rectangle is 11 cm, and the length is 3 times that, or 33 cm.
_____
Using variables, we can let w represent the width. Then 3w can represent the length, and the area is ...
A = LW
A = (3w)(w) = 3x^2 = 363
w^2 = 363/3 = 121
w = √121 = 11
3w = 3·11 = 33
The width is 11 cm; the length is 33 cm.
7/3=2.3 but you can't have a desamal so it would be 2.
Answer: cost of 1 pot of ivy = $12
Cost of 1 rose bush =$ 10
Step-by-step explanation:
Step 1
Let rose bushes be represented as r
and pot of ivy be represented as p
such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as
7 r + p = 82----- eqn 1
Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as
5r +2 p = 74----- eqn 2
Step 2
Solving
7 r + p = 82----- eqn 1
5r +2 p = 74----- eqn 2
By elimination method Multiply eqn 1 by 5 and eqn 2 by 7
35r+ 5p= 410--- eqn 3
35r+ 14p =518--- eqn 4
Subtracting eqn 4 from eqn 3
9p = 108
p = 108/9
p=12
p = pot of ivy = $12
therefore rose bush wll be ( from equation 1)
7r+ p= 82
7r=82-12
7r= 70 r= 70/7
r= rose bush =$ 10
