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Andrei [34K]
3 years ago
7

A sample statistic becomes more accurate as the same size increases due to

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Idk what you r asking help

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What is factored form of 4x3 + 3x2 + 8x + 6?
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The answer is (4x+3) (x^2+2)
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Explain how 2 different squares can be made using the number 9.
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You can make two squares with 8, and put a line through one of them making one square two triangles put together.
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The radius of a. circular garden is 15 feet. About how much fencing will be needed to enclose the garden?
WINSTONCH [101]

Answer:

94.2 ft of fencing

Step-by-step explanation:

To answer this, find the circumference, C, of the garden, using the circumference formula C = 2(pi)r.

Here, with r = 15 ft, we get C = 2(3.14)(15 ft) = 94.2 ft of fencing will enclose this garden.

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What is (27/8)^-2/3 ?
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Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
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