Answer:
# The transformation of f(x) to be g(x) is
- Reflected across the x-axis
- Translated 7 units to the left
- Translated 6 units up
# The transformation of f(x) to be g(x) is
- Reflected across the y-axis
- Translated 7 units down
Step-by-step explanation:
* Lets revise some transformation rules
* Lets talk about the transformation
- If the function f(x) reflected across the x-axis, then the new
function g(x) = - f(x)
- If the function f(x) reflected across the y-axis, then the new
function g(x) = f(-x)
- If the function f(x) translated horizontally to the right
by h units, then the new function g(x) = f(x - h)
- If the function f(x) translated horizontally to the left
by h units, then the new function g(x) = f(x + h)
- If the function f(x) translated vertically up
by k units, then the new function g(x) = f(x) + k
- If the function f(x) translated vertically down
by k units, then the new function g(x) = f(x) – k
* Lets solve the problems
# f(x) = 2^x ⇒ g(x) = -(2)^(x + 7) + 6
- There is a -ve sign in-front of the 2
∵ f(x) will be -f(x)
∴ f(x) will reflect across the x-axis ⇒ (1)
- The power x becomes x + 7
∵ -f(x) will be -f(x + 7)
∴ -f(x) will translate 7 units to the left ⇒ (2)
- after that -f(x + 7) add by 6
∴ -f(x + 7) will translate 6 units up ⇒ (3)
- From (1) , (2) , (3)
∴ The transformation of f(x) to be g(x) is
- Reflected across the x-axis
- Translated 7 units to the left
- Translated 6 units up
# f(x) = ㏒(x) ⇒ g(x) = ㏒(-x) - 7
- The (x) will be (-x)
∵ f(x) will be f(-x)
∴ f(x) will reflect across the y-axis ⇒ (1)
- after that f(-x) subtracted by 7
∴ f(-x) will translate 7 units down ⇒ (2)
- From (1) , (2)
∴ The transformation of f(x) to be g(x) is
- Reflected across the y-axis
- Translated 7 units down
* For more understand look to the attached graphs
# First function:
- f(x) is the red
- g(x) is the blue
# Second function:
- f(x) is the black
- g(x) is the green
Answer:
CD ≠ EF
Step-by-step explanation:
Using the distance formula
d =
with (x₁, y₁ ) = C(- 2, 5) and (x₂, y₂ ) = D(- 1, 1)
CD =
=
= =
Repeat using (x₁, y₁ ) = E(- 4, - 3) and (x₂, y₂ ) = F(- 1, - 1)
EF =
=
= =
Since ≈
, then CD and EF are not congruent
Answer:
a.y'=-1
b.y'=-1
c.Yes
Step-by-step explanation:
We are given that consider a function
Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable
Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.
a.
Differentiate w.r.t x then we get
b.
Differentiate w.r.t x then we get
When we substituting the value of y obtained from part b into a solution of part a then we get
Hence, solutions are consistent.