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2 years ago

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Bernard is 5 times older than Victor. Victor is five years older than Peter. If the sum of their ages is 65 years, how old will

Victor be in 7 years? *

1 answer:

Iteru [2.4K]2 years ago

7 0

Answer:

Victor's age after 7 years = 10+7

=> 17 years

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The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere?

frosja888 [35]

Answer:

256π/3 cm³

Step-by-step explanation:

d = 2r => r = d/2 = 4cm/2 = 2 cm

V(sphere) = 4π·r³/3

= 4π·64/3 cm³

= 256π/3 cm³

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3 years ago

Need help on this question i dont get it ima be posting some more but i need help on this on first

Anuta_ua [19.1K]

Answer:

The answer is B.

Step-by-step explanation:

Its B because in the problem it says $12 per yard which means it would be 12y. The 40 Rupesh already had so just add it and it would be 12y+ 40. The key word "At least" results into the sign being greater than or equal to. So the final answer would be 12y+40 $\geq$ 148.

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2 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

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2 years ago

Solve the equation f/3+22=17

andrezito [222]

1) f/3 + 22 = 17

2) f/3 + 22 - 22 = 17 - 22

= f/3 = -5

3) 3 • f/3 = 3(-5)

= f = 3(-5)

= f = -15

Your answer would be f = -15

:)

4 0

2 years ago

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The base of a regular pyramid is a hexagon.

forsale [732]

The triangle in the drawing is semi equilateral. Therefore a=√(14^2-7^2)=12.12 cm
The base of a regular pyramid consists of 6 equilateral triangles. The area of each triangle is: (14*12.12)/2 = 84.87 cm^2
The base: 6*84.87=509.22 cm^2

5 0

2 years ago

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