All categories

3 years ago

Eight less than the quotient of a number and 3 is 18. Which equation models this sentence?

Mathematics

2 answers:

labwork [276]3 years ago

8 0

B- n/ 3 - 8 = 18....................

Yuki888 [10]3 years ago

5 0

Answer:

$\frac{n}{3}-8=18$

Step-by-step explanation:

Eight less than the quotient of a number and 3 is 18.

Let the unknown number be 'n'

the quotient of a number and 3. For quotient we divide by 3

$\frac{n}{3}$

Eight less than the quotient of a number and 3

For eight less , we subtract 8 from the division

$\frac{n}{3}-8$

The above expression is equal to 18

Eight less than the quotient of a number and 3 is 18.

$\frac{n}{3}-8=18$

You might be interested in

To join a video rental club, a member pays an initial fee plus an additional monthly cost. The equation below describes the rela

kobusy [5.1K]

The answer is c because there asking for the rate of change which is $20 per month

7 0

3 years ago

What is the y-intercept of f (x) = 3.4’x?

klasskru [66]

Answer:

Step-by-step explanation:

Y intercept when x = 0

F(0) = 3 * 4^(0) = 3 * 1 = 3

5 0

1 year ago

What is the distance between the points (10, -7) and ( 10, 9) on the coordinate plane?

xenn [34]

16 on the y-axis, 0 on the x axis

7 0

3 years ago

What are the next three terms in the sequence3,6,9,12,...?

Vinil7 [7]

Answer:

15, 18, 21

Step-by-step explanation:

3, 6, 9, 12, 15, 18, 21...

3 x 5 = 15

3 x 6 = 18

3 x 7 = 21

Hope this helps! :)

8 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago