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Svetach [21]
3 years ago
12

Prob the last two, but wtvvv. HELP THOO

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0

Answer:

Combine the ones to make 8 ones

Step-by-step explanation:

It seems the most reasonable. (Also, all the other options are wrong-) I just don't see why it's making you go through this process when you can just add 12 + 6 in your head lol.

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There are 27
kotegsom [21]

Answer:

3 players

Step-by-step explanation:

So, all you have to do is multiply 27 by 1/9 to get 3. Or, you could try figure out what number needs to be multiplied by 9 to get 27, which is also 3.

6 0
3 years ago
Find an equation of the line with the given slope that passes through the given point. Write the equation in Ax+By=C M=7/5 and t
pychu [463]
Y=7/5× -71/5
plug in the points into the y=mx+b equation and solve from there and of course there are Fractions so you have to make the same denominators but is just an extra step
6 0
3 years ago
Jane,our class Chihuahua,had 2 3/4 cups of dog treats.She ate the same amout each day for 5 days until all the treats were gone.
aivan3 [116]
Jane will eat 0.55 cup or 11/20 cup because you will need to divide 2 3/4 by 5
6 0
3 years ago
Evaluate the function f(x) = 2x3 - 6x + 1 for f(-2).
erma4kov [3.2K]

Answer:

- 3

Step-by-step explanation:

f(x) = 2 {x}^{3}  - 6x + 1 \\ plugging \: x =  - 2 \\ f( - 2) = 2( { - 2})^{3}  - 6( - 2)+ 1  \\  = 2 \times ( - 8) + 12 + 1 \\  =  - 16 + 13 \\  =  - 3 \\ f( - 2) =  - 3

7 0
4 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
4 years ago
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