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WINSTONCH [101]
4 years ago
9

Help please. thank u :)

Mathematics
1 answer:
Sveta_85 [38]4 years ago
5 0

Answer:

help

Step-by-step explanation:

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A furniture store pays a wholesale price for a mattress.
WITCHER [35]

Answer:

Step-by-step explanation:

Part A:

Given that the mattress is sold for 50% off of the retail price, let the retail price of the mattress be x, then

50% of x = 1200

⇒ 0.5x = 1200

⇒ x = 1200 / 0.5 = 2400

Therefore, the retail price of the mattress, before the discount is $2,400.

Part B:

Given that the store marks up the retail price to 150% of the wholesale price. Let the whole sale price be p, then

(100% + 150%) of p = 2400

250% of p = 2400

2.5p = 2400

p = 2400 / 2.5 = 960.

Therefore, the wholesale price, before the markup was $960

7 0
3 years ago
X y
aalyn [17]
Answer is
<span>C) y = -2x + 3 </span>

when x = 0, y = 3
when x = 1, y = -2(1) + 3 = -2 + 3 = 1
when x = 2, y = -2(2) + 3 = -4 + 3 = -1

solutions matched the table above
5 0
3 years ago
Read 2 more answers
PLEASE HELP ME SOLVE THIS QUESTION ASAPPPPPPPPPPP
AveGali [126]

Answer:

Step-by-step explanation:

Volume of the pyramid :

V=\dfrac{x^2*h}{3} =554.9\\\\x^2*h=554.9*3\\\\h=15.1\\\\x^2*15.1=554.9*3\\\\x^2=\dfrac{554.9*3}{15.1} \\\\x=\sqrt{\dfrac{1664,7}{15.1} } \\\\x=\sqrt{110,24503311258278145695364238411...} \\\\x=10,499763478887644993681148554978...\approx{10.50}

8 0
3 years ago
A synthetic fiber used in manufacturing carpet has a tensile strength that is normally distributed with a mean 75.5 psi and stan
yKpoI14uk [10]

Answer:

43.25% probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 75.5, \sigma = 3.5, n = 6, s = \frac{3.5}{\sqrt{6}} = 1.43

Find the probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.

This is 1 subtracted by the pvalue of Z when X = 75.75. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{75.75 - 75.5}{1.43}

Z = 0.17

Z = 0.17 has a pvalue of 0.5675.

1 - 0.5675 = 0.4325

43.25% probability that a random sample of n = 6 fiber specimens will have a sample tensile strength that exceeds 75.75 psi.

5 0
4 years ago
Becky graphs a system of two linear equations and determines that (1,5) and (3,7) are solutions. What does the graph of the syst
KonstantinChe [14]

Is that from a textbook or a worksheet word problem?

5 0
3 years ago
Read 2 more answers
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