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faltersainse [42]
3 years ago
12

Yes

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

the answer is A. 1.1 mentions

Answer:

the answer is A. 1.1 mentions

Step-by-step explanation:

mark me brainiest and stop giving garbage answers your not contributing to the community

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4) A window is in the form of a rectangle surmounted by a semicircle. The rectangle is of clear glass, whereas the semicircle is
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Answer:

l=0.1401P\\

w =0.2801P

where P = perimeter

Step-by-step explanation:

Given that a window is in the form of a rectangle surmounted by a semicircle.

Perimeter of window =2l+\pid/2+w

P= 2l+3.14 (w/2)+w

Or P = 2l+2.57w\\l = \frac{P-2.57w}{2}

To allow maximum light we must have maximum area

Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle

A=lw +\pi \frac{w^2}{8}

A=lw +\pi \frac{w^2}{8}\\A=w*\frac{P-2.57w}{2}+0.3925w^2\\2A= Pw-2.57w^2+(0.785w^2)\\2A' = P-5.14w+1.57 w\\2A" =-5.14+1.57

Hence we get maximum area when i derivative is 0

i.e. P-5.14w+1.57 w=0\\3.57w =P\\w = \frac{P}{3.57} =0.2801P

l = \frac{P-2.57w}{2}\\l = 0.1401P

Dimensions can be

l=0.1401P\\w =0.2801P

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