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Tpy6a [65]
4 years ago
11

Examine the diagram and information to answer the question. Rectangle EFGH has vertices at E(7,7), F(1,5), G(2,2), and H(8,4). H

ow many units is the perimeter of rectangle EFGH?

Mathematics
1 answer:
schepotkina [342]4 years ago
7 0

Answer:

Perimeter of rectangle = 6√10 units (the attachment isnt clear. It seems the answer is in option B)

Step-by-step explanation:

First we find the distance of the length and width of the rectangle.

Distance between E and F = Distance EF

Distance EF = √(∆y²-∆x²)

= √[(5-7)² + (1-7)²] = √[(-2)² + (-6)²]

= √(4+36) = √40

Distance EF = 2√10

Distance between F and G = Distance FG

Distance FG = √(∆y²-∆x²)

= √[(2-5)² + (2-1)²] = √[(-3)² + (1)²]

= √(9+1) = √10

Distance FG = √10

Length= distance EF = distance HG

And width = distance FG = distance EH

Perimeter of rectangle = 2(length + width)

Perimeter of rectangle = 2(2√10 + √10)

= 2(3√10)

Perimeter of rectangle = 6√10 units (the attachment isnt clear. It seems the answer is in option B)

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Answer:

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Step-by-step explanation:

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Here, R is the annual revenue in millions of dollars, x is the number of years since January 1, 1980.

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So, R=790\\-40|x-11|+990=790\\40|x-11|=200\\|x-11|=5\\x-11=5\text{ (or) }x-11=-5\\x=16\text{ (or) }x=6

       So, after 6 yrs and 16 yrs from January 1, 1980, the Passenger revenue equals $ 790 million.

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Step-by-step explanation:

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