1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andreyandreev [35.5K]
2 years ago
14

One x-intercept for a parabola is at the point (0.5,0). Use the factor method to find the other x-intercept for the parabola def

ined by this equation: y=4×^2+8x-5
Mathematics
1 answer:
makvit [3.9K]2 years ago
7 0

Answer: (-5/2,0) is the other x intercept.


Step-by-step explanation:

Make use of given fact that (x - 1/2) is a factor of the polynomial.

Divide 4x^2 + 8x - 5 by (x - 1/2)

Partial quotient 4x.

Subtract 4x × (x - 1/2) = 4x^2 - 2x from dividend giving 10x - 5 remainder.

Second partial quotient is 10,

10 × (x - 1/2) = 10x - 5, remainder zero

(x - 1/2)(4x + 10) = 4x^2 + 8x - 5

Graph of the parabola crosses the x axis where 4x+10=0, x = -5/2.

You might be interested in
Rita has a loan of 40,000. This loan has a simple interest rate of 6% per year. What is the amount of interest that rita will be
kvv77 [185]

Answer:

........

Step-by-step explanation:

7 0
3 years ago
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

5 0
3 years ago
9(5x) need help asap​
dexar [7]

Answer:

45x happy to help ya :)

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
If one of the sides of the regular polygon pictured has a side length of 3x+2, what is the length of all the sides
leonid [27]

Answer:

3x+2

Step-by-step explanation:

The polygon is regular ,<em> </em>so all the sides would be equal.

Thus all sides measure same as <u>3x</u><u>+</u><u>2</u>

7 0
2 years ago
PLEASE HELP!! URGENT!! i will mark brainliest if its right!! In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and DF ≅ BD. Point C is
zvonat [6]

Answer:

See below.

Step-by-step explanation:

This is how you prove it.

<B and <F are given as congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

<DEC and <DCE are given as congruent.

Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

Now you need another side to do either AAS or ASA.

Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.

Now you have 1 pair of included sides congruent ABC and GFE.

Now using ASA, you prove triangles ABC and GFE congruent.

7 0
3 years ago
Other questions:
  • ABCD is a parallelogram and line CD = line DA. determine whether the parallelogram is a rhombus. if so by which property?
    10·2 answers
  • The endpoints of AB are A(2, 3) and B(8, 1). The perpendicular bisector of AB is CD, and point C lies on AB. The length of CD is
    10·1 answer
  • There is a picture with the question can anyone help me.
    13·1 answer
  • The square shown is dilated by a scale factor of 2. The center of dilation is point C. Which shows the correct image, A’
    7·2 answers
  • 2.-3(x-2) OS<br> (1 Point)<br> Enter your answer
    15·1 answer
  • Expand and Simplify<br> 10a-(3a+7)
    5·1 answer
  • What letter ??????????????????????
    11·1 answer
  • patrick is thinking of a number. his number is twice as large as the smallest number that rounds to 30 when rounding to the near
    5·1 answer
  • 1. Find the slope<br> (1 point)<br><br> 2<br> -1/2<br> -2<br> 1/2
    5·2 answers
  • (1) A bag contains 3 red balls,5 blue
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!