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yanalaym [24]
3 years ago
13

Ju Chan solved the previous question by finding the expression 4(-15). Which addition problem would give the same result? Choose

all that apply. A . 15 + 15 + 15 + 15
A . 15 + 15 + 15 +15 B . 4 + 4 + 4 + 4
C . (–1)(15 + 15 + 15 + 15)
D . (–15) + (–15) + (–15) + (–15)
Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

C. (-1)(15+15+15+15)

D. (-15)+(-15)+(-15)+(-15)

Step-by-step explanation:

The original expression: 4(-15)=-60

Let's try choice A: 15+15+15+15=60(not a negative number, so does not work)

Let's try choice B: 4+4+4+4=16(nowhere near -60)no

Let's try choice C: (-1)(15+15+15+15)=(-1)(60)=-60--yes

Let's try choice D: (-15)+(-15)+(-15)+(-15)=-60--yes

Only choices C and D work.

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Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.

complex-numbers

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edited Mar 6 '17 at 4:38

Richard Ambler

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asked Mar 6 '17 at 3:34

14wml

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Add a comment

1 Answer

1

No. It is not true that =cos()+sin(). Notice that

1=1≠cos()+sin(),

for example consider this at =0.

As a hint for figuring this out, notice that

+=ln(+)

then recall your rules for logarithms to get this to the form (+)ln().

8 0
3 years ago
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