Answer:
t=√d-12/4 and t=√-d-12/4, d≥12
Step-by-step explanation:
Hope this helps.
The equation that represents the line that is perpendicular is
3y + 5x = -42
The standard equation of a line in point-slope form is expressed as:

- m is the slope of the lne
- (x1, y1) is any point on the line.
- Given the equation y = 3/2x + 1, the slope of the line is 3/5
- The s<u>lope of the line perpendicular</u> is -5/3
Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

Hence the equation that represents the line that is perpendicular is
3y + 5x = -42
Learn more on equation of a line here:brainly.com/question/19417700
X = 47 + 9y
xy = 1860
y(47 + 9y) = 1860
47y + 9y² = 1860
9y² + 47y - 1860 = 0
> using a quadratic equation solver on a calculator but you can also use the quadratic equation = [-b+/- √(b²-4ac)]/(2a)
> only integer solution is x = 12
12y = 1860
y = 155
integers are 12 and 155