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Alisiya [41]
3 years ago
13

The probability that a biased dice will land on a six is 0.4. Marie is going to throw the dice 400 times. Work out an estimate f

or the number of times the dice will land on a six.

Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0
I’m pretty sure it’s 16...?

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100th term for 5, 2, -1
andrezito [222]

Answer:

100th term = -1485

Step-by-step explanation:

<h3>Arithmetic Progressionthe </h3><h3>nth term, Tn:</h3>

t_{n} = a + (n - 1)d

n = number of terms

= 100

a = first term

= 5

d = difference

= second term - first term

= 2 - 5

= -3

substitute the values into the formula

t_{100} = 5(100  - 1)( - 3)

t_{100} = 5(99)( - 3)

t_{100}  = 495( - 3)

t_{100}  =  - 1485

8 0
3 years ago
Story Problem
LenKa [72]
14.95 would be the answer
3 0
3 years ago
Find three consecutive odd integers whose sum is -21
nadezda [96]
X+ (x+2)+ (x+4)= -21
3x+6=-21
3x=-27
x=-9

Final answer: -9, -7, -5
3 0
3 years ago
Saiges spaceship traveled 588 kilometers in 60 seconds. Determine whether or not each spaceship trip below has the same speed as
Fiesta28 [93]

Answer:

Part 1)  441km in 45s   --> Has the same speed as Saige's spaceship

Part 2) 215km in 25s --> Does not have the same speed as  Saige's spaceship

Part 3) 649km in 110s --> Does not have the same speed as  Saige's spaceship

Step-by-step explanation:

<u><em>The complete question is</em></u>

Saige's spaceship traveled 588 kilometers in 60 seconds.

Determine whether or not each spaceship trip below has the same speed as Saige's spaceship.

441km in 45s

215km in 25s

649km in 110s

we know that

The speed is equal to divide the total distance traveled by the total time

In this problem we have that

The speed of Saiges spaceship is equal to

\frac{588}{60}=9.8\ \frac{km}{sec}

case 1) we have

441km in 45s

Find out the speed of the  spaceship trip

\frac{441}{45}=9.8\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

9.8\ \frac{km}{sec}=9.8\ \frac{km}{sec}

therefore

Has the same speed as Saige's spaceship

case 2) we have

215km in 25

s

Find out the speed of the  spaceship trip

\frac{215}{25}=8.6\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

8.6\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}

therefore

Does not have the same speed as  Saige's spaceship

case 3) we have

649km in 110s

Find out the speed of the  spaceship trip

\frac{649}{110}=5.9\ \frac{km}{sec}

Compare the speed of the spaceship trip with the speed of Saiges spaceship

5.9\ \frac{km}{sec}\neq 9.8\ \frac{km}{sec}

therefore

Does not have the same speed as  Saige's spaceship

6 0
3 years ago
Read 2 more answers
What is the vertical distance between (-1,-3) and (-4,-12)?
sasho [114]

Answer:

Use the distance formula to determine the distance between two points.

Exact Form:

3 √ 10

Decimal Form:

9.48683298 …

Step-by-step explanation:

Hope this helps! Have a great day!

8 0
3 years ago
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