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PilotLPTM [1.2K]
3 years ago
10

I know the answer already but can someone explain it please 2187= 3^x Answer is x=7

Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer:

3^x = 2187 is equivalent to log 3 (2187) = x.  (the three is the small number that goes lower next to the g). Then, use a calculator to do log(2187) / log(3)

Step-by-step explanation:

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Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro
strojnjashka [21]

Answer:

The missing side is B = 6.0\ cm

The missing angles are \alpha = 56.2 and \theta = 93.8

Step-by-step explanation:

Given

A = 10\ cm

C = 12\ cm

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The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with \alpha

Angle B with \beta

Angle C with \theta

Calculating B

This will be calculated using cosine formula as thus;

B^2 = A^2 + C^2 - 2ACCos\beta

Substitute values for A, C and \beta

B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30

B^2 = 100 + 144 - 240 * 0.8660

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B^2 = 36.2

Take Square root of both sides

B = \sqrt{36.2}

B = 6.0 <em>(Approximated)</em>

Calculating \alpha

This will be calculated using cosine formula as thus;

A^2 = B^2 + C^2 - 2BCCos\alpha

Substitute values for A, B and C

A^2 = B^2 + C^2 - 2BCCos\alpha

10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha

100 = 36 + 144 - 144Cos\alpha

Collect Like Terms

100 - 36 - 144 = -144Cos\alpha

-80 = -144Cos\alpha

Divide both sides by -144

\frac{-80}{-144} = Cos\alpha

0.5556 = Cos\alpha

\alpha = cos^{-1}(0.5556)

\alpha = 56.2 <em>(Approximated)</em>

Calculating \theta

This will be calculated using cosine formula as thus;

C^2 = B^2 + A^2 - 2BACos\theta

Substitute values for A, B and C

12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta

144 = 36 + 100 - 120Cos\theta

Collect Like Terms

144 - 36 - 100 = -120Cos\theta

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Divide both sides by -120

\frac{8}{-120} = Cos\theta

-0.0667= Cos\theta

\theta = cos^{-1}(-0.0667)

\theta = 93.8 <em>(Approximated)</em>

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Step-by-step explanation:

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