W = kL where W = weight supported, L = length of the beam and k is constant of variation.
Substituting the given values:-
310 = 2k
k = 155
so equation of variation is W = 155L
For length 10 m the weight it can support is
W = 155*10 = 1550 kg answer
Answer:
xsquared+8x+15
Step-by-step explanation:
xsquared+3x+5x+15
xsquared+8x+15
Let number of quarters in family piggy bank = x
Let number of dimes in family piggy bank = y
Given that "there are 12 times as many dimes are there are quarters". so we can write equation:
y=12x...(i)
Given that " total change is worth $21.75".
We know that 1 quarter = $0.25 and 1 dime = $0.10
So other equation will be :
0.25x+0.10y=21.75...(ii)
Now we just need to solve both equations.
Plug (i) into (ii)
0.25x+0.10y=21.75
0.25x+0.10(12x)=21.75
0.25x+1.2x=21.75
1.45x=21.75
x=15
plug x=15 into (i)
y=12x=12*15=180
Hence final answer is given as:
Number of quarters in family piggy bank = 15
Number of dimes in family piggy bank = 180
I believe it would be multiplied by -0.5 or -1/2.
