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Nadusha1986 [10]
3 years ago
11

the derivative of the function f is given by f'(x)=x^2cos(x^2). How many points of inflection does the graph of f have on the op

en interval (-2,2)
Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0
The point of inflection is calculated by equating the second derivative to zero and determining x from there.

f"(x) = -x²2xsinx² + cosx²(2x) = 0

2xcosx² - 2x³sinx² = 0
2x (cosx² - xsinx²) = 0

2x = 0   ⇒  x = 0
cosx² - xsinx² = 0   ⇒ x = 3.82 (if you use shift+solve in your scientific calculator)

Thus, the function only has 1 point of inflection and it is at x = 0.
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Answer

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Step-by step explanation

I used p for plates and b for bowls\

2p+12b=4+(4*2)

2p+12b=12

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3 years ago
The formula for the lateral area of a right cone is LA = rs, where r is the radius of the base and s is the slant height of the
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Answer:

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s = \frac{LA}{r}s=

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r = \frac{LA}{s}r=

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To make r, the subject of the equation, divide both sides of the equation by s

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Step-by-step explanation:

the Answer is Above The Image Or The Answer box

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Graph 3x+y=-10 -x+3y=0
nikdorinn [45]

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

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3x+y=-10            <em>subtract 3x from both sides</em>

y=-3x-10

-x+3y=0             <em>add x to both sides</em>

3y=x             <em>divide both sides by 3</em>

y=\dfrac{1}{3}x

-----------------------------------------------------

We need only two points to plot a graph of each function.

y=-3x-10

for x = 0 and for x = -3:

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