The formula for obtaining the value of a term of a sequence is given as a
as a recursive formula.
Responses:
- The information as a sequence is; R1, 2·R1, 4·R1, 8·R1, 16·R1, ...
- The sequence of the information is a geometric sequence
<h3>How is the given information expressed as a sequence?</h3>
The amount of pocket money Smith gets = 2 × The amount he gets in the previous day
The amount Smith gets on the first day = R1
Required:
The given information expressed as a sequence.
Solution:
The amount of money smith gets can be expressed as follows;
Amount he gets on day 1 = R1
On day 2, R2 = 2·R1
On day 3, R3 = 2·R2 = 2·2·R1 = 4·R1
On day 4, R4 = 2·R3 = 2·2·2·R1 = 8·R1
On day 5, R5 = 2·R4 = 2·2·2·2··R1 = 16·R1
The information written as a sequence is therefore;
- R1, 2·R1, 4·R1, 8·R1, 16·R1, ...
- The type of sequence is a<u> geometric sequence, or progression</u> where the first term is R1, and the common ratio, r = 2
Learn more about geometric sequence here:
brainly.com/question/4289731
brainly.com/question/1532378
9514 1404 393
Answer:
r ≈ 19.0
s ≈ 17.7
Step-by-step explanation:
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
So, you have ...
cos(43°) = r/26
r = 26·cos(43°) ≈ 19.0
__
sin(43°) = s/26
s = 26·sin(43°) ≈ 17.7
If the number only has 2 digits, it could only be 91, because since the tens digit is 8 more than the ones digit, the tens digit is greater than or equal to 8. it cannot be 10 or more, because that would make the number over 100, leaving only 8 and 9. If the tens digit is 8, the ones digit is zero, and since it cannot be zero, then the tens digit must be 9, leaving the ones digit to be 1. So, the final answer is 91.
1 = 7/7 charlie should know
Solution :
a). The probability that the student will 
the 1st question after the 4th attempt.
P (correct in the 4th attempt)
= 
= 0.01171875
b). The probability that the student will 3 questions after 10 total attempts.
P( X = 3) for X = B in (n = 10, p = 0.75)
= 
= 0.0031
c). The mean and the standard deviation for the number of attempts up to when the students gets all the questions correct is :
There are = 6 success, p = 0.75.
Therefore, this is a case of a negative binomial distribution.
= 8
So, 
= 1.6330
