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stellarik [79]
3 years ago
6

My number has a tens digit that is 8 more than the ones digit. Zero is not one of my digits

Mathematics
2 answers:
Mice21 [21]3 years ago
6 0

in the event that the number just has 2 digits, it must be 91, in light of the fact that since the tens digit is 8 more than the ones digit, the tens digit is more noteworthy than or equivalent to 8. it can't be at least 10, since that would make the number more than 100, leaving just 8 and 9. On the off chance that the tens digit is 8, the ones digit is zero, and since it can't be zero, at that point the tens digit must be 9, leaving the ones digit to be 1. In this way, the last answer is 91.

Further Explanation:

Explanation:

Data:

in the event that the number just has 2 digits, it must be 91, in light of the fact that since the tens digit is 8 more than the ones digit, the tens digit is more noteworthy than or equivalent to 8.  

Calculation:

it can't be at least 10, since that would make the number more than 100, leaving just 8 and 9.

Solution:

On the off chance that the tens digit is 8, the ones digit is zero, and since it can't be zero, at that point the tens digit must be 9, leaving the ones digit to be 1. In this way, the last answer is 91.

Answer Details:

Subject: Mathematics  

Level: middle school

Key Words:

Explanation:

Diagnose of cancer of lungs:

For further Evaluation

brainly.com/question/10872128

brainly.com/question/4379740

kakasveta [241]3 years ago
5 0
If the number only has 2 digits, it could only be 91, because since the tens digit is 8 more than the ones digit, the tens digit is greater than or equal to 8. it cannot be 10 or more, because that would make the number over 100, leaving only 8 and 9. If the tens digit is 8, the ones digit is zero, and since it cannot be zero, then the tens digit must be 9, leaving the ones digit to be 1. So, the final answer is 91.
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