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mr Goodwill [35]
3 years ago
13

The pressure of a gas p(v) varies inversely with the volume of the gas v. The pressure of a gas measures 25 kg/cm^2 when its vol

ume is 200cm^2. Which equation can be used to find the pressure of the gas when the volume is changed?
A.p(v)=8/v
B.p(v)=8v
C.p(v)=5000/v
D.p(v)=5000v
Mathematics
1 answer:
Mashcka [7]3 years ago
5 0

\bf \qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{\underline{p(v)} varies inversely with \underline{v}}}{p(v)=\cfrac{k}{v}}\qquad \textit{we also know that } \begin{cases} p(v)=25\\ v=200 \end{cases} \\\\\\ 25=\cfrac{k}{200}\implies 5000=k\qquad therefore\qquad \boxed{p(v)=\cfrac{5000}{v}}

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the board is 56 inches long.

how i did this was

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<em>hope this helps :)</em>

7 0
3 years ago
Just number 2 please i’ve tried many times... i need an equation and the answer :)
Triss [41]

Keller collected $62.48 and Izzy collected $47.83 and J collected $19.98

Step-by-step explanation:

Step 1; Assume that J collected $x, Keller collected $y and Izzy collected $z. All three combined collected $125.95, so

x + y + z = 125.95, take this as equation 1.

From the given data, the following equations can be formed.

y = 42.50 + x or x = y - 42.50 take this as equation 2 and

y = 15 + z, take this as equation 3.

Step 2; Now we must determine x and y in terms of z, so that equation 1 can be solved (the equations can be in terms of any term x, y or z.)

Rearranging equation 2 and 3,

we get 15 + z so  x = y - 42.50, y = x = 15 + z - 42.50, take this as equation 4,

If we substitute equations 4, 2 in 1, we get

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3z = 142.45, so z = 47.833.

Substitute z = 47.833 in equation 3.

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Substitute y = 62.4833 in equation 2,

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Rounding of the values of x,y, and z to nearest hundredth we get

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7 0
3 years ago
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3 0
3 years ago
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