Answer: 918km^2
Step-by-step explanation:
![area(a): 1700km^2\\percentage(p): 5.75 = \frac{5.75}{100}=0.0575\\years(y): 8](https://tex.z-dn.net/?f=area%28a%29%3A%201700km%5E2%5C%5Cpercentage%28p%29%3A%205.75%20%3D%20%5Cfrac%7B5.75%7D%7B100%7D%3D0.0575%5C%5Cyears%28y%29%3A%208)
Let x be the new dimension of the area;
![x=a-(a*p*y)](https://tex.z-dn.net/?f=x%3Da-%28a%2Ap%2Ay%29)
![x=(1700km^2)-(1700km^2*0.0575*8)\\x=1700km^2-782km^2\\x=918km^2](https://tex.z-dn.net/?f=x%3D%281700km%5E2%29-%281700km%5E2%2A0.0575%2A8%29%5C%5Cx%3D1700km%5E2-782km%5E2%5C%5Cx%3D918km%5E2)
Answer: 2.093
Step-by-step explanation:
As per give , we have
Sample size : n= 20
Degree of freedom : df= n-1=19
Significance level : ![\alpha: 1-0.95=0.05](https://tex.z-dn.net/?f=%5Calpha%3A%201-0.95%3D0.05)
Since , the sample size is small (n<30) so we use t-test.
For confidence interval , we find two-tailed test value.
Using students's t-critical value table,
Critical t-value : ![t_{\alpha/2, df}=t_{0.025,19}=2.093](https://tex.z-dn.net/?f=t_%7B%5Calpha%2F2%2C%20df%7D%3Dt_%7B0.025%2C19%7D%3D2.093)
Thus, the critical value for the 95% confidence interval = 2.093
Associative Property if Addition
Answer:
Step-by-step explanation:
y + 5 = -4(x - 2)
the answer is A
I hope this helps you
x+0,2x=1-0,7
1,2x=0,3
x=0,3/1,2
x=1/4
x=0,25